A particle moves in one dimension x under the influence of a potential V(x) as sketched in the figure below. The shaded region corresponds to infinite V, i.e., the particle is not allowed to penetrate there. V(x) -Vo 0 a X If there is an energy eigenvalue E = 0, then a and V, are related by

icon
Related questions
Question
A particle moves in one dimension x under the influence of a potential V(x) as
sketched in the figure below. The shaded region corresponds to infinite V, i.e., the
particle is not allowed to penetrate there.
V(x)
a
b
a²Vo =
If there is an energy eigenvalue E = 0, then a and V, are related by
a²Vo =
(n + ² ) ² n²
2m
3-1
n²π²
2m
a²V₁ =
(n + ²) π ²
2m
-Vo
nπ²
0
a
X
Transcribed Image Text:A particle moves in one dimension x under the influence of a potential V(x) as sketched in the figure below. The shaded region corresponds to infinite V, i.e., the particle is not allowed to penetrate there. V(x) a b a²Vo = If there is an energy eigenvalue E = 0, then a and V, are related by a²Vo = (n + ² ) ² n² 2m 3-1 n²π² 2m a²V₁ = (n + ²) π ² 2m -Vo nπ² 0 a X
Expert Solution
steps

Step by step

Solved in 2 steps with 2 images

Blurred answer