A particle of mass 2.0 kg moves under the influence of the force F(x) = (-5x² = 7x) N. Suppose a frictional force also acts on the particle. If the particle's speed when it starts at x = -4.0 m is 0.0 m/s and when it arrives at x = -4.0 m is 9.0 m/s, how much work is done on it by the frictional force between x = -4.0 m and x = 4.0 m?
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