A particle starts moving from the origin at time t = 0 with the dot production of the position vector and the velocity vector given by rv = k²t, where k is a constant. 1. Express the dot product rv as a time derivative(). Hint: remember that for two vectors A and B, (A. B) = d.B + A. B dt dt 2. What is the distance of the particle from the origin after 4 seconds?
A particle starts moving from the origin at time t = 0 with the dot production of the position vector and the velocity vector given by rv = k²t, where k is a constant. 1. Express the dot product rv as a time derivative(). Hint: remember that for two vectors A and B, (A. B) = d.B + A. B dt dt 2. What is the distance of the particle from the origin after 4 seconds?
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![A particle starts moving from the origin at time t=0 with the dot production of the
position vector and the velocity vector given by rv = k2t, where k is a constant.
●
1. Express the dot product r v as a time derivative().
d
Hint: remember that for two vectors A and B, (AB) =
, (A. B) =
2. What is the distance of the particle from the origin after 4 seconds?
dA
A A·B+ A. d
dB
dt
dt](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F72d5acfa-3b7d-4411-a376-7057db7a870b%2F074c143d-9255-4fec-9981-cd7ac7d4010d%2F9x1tu8f_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A particle starts moving from the origin at time t=0 with the dot production of the
position vector and the velocity vector given by rv = k2t, where k is a constant.
●
1. Express the dot product r v as a time derivative().
d
Hint: remember that for two vectors A and B, (AB) =
, (A. B) =
2. What is the distance of the particle from the origin after 4 seconds?
dA
A A·B+ A. d
dB
dt
dt
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