A particle starts moving from the origin at time t = 0 with the dot production of the position vector and the velocity vector given by rv = k²t, where k is a constant. 1. Express the dot product rv as a time derivative(). Hint: remember that for two vectors A and B, (A. B) = d.B + A. B dt dt 2. What is the distance of the particle from the origin after 4 seconds?

icon
Related questions
Question
A particle starts moving from the origin at time t=0 with the dot production of the
position vector and the velocity vector given by rv = k2t, where k is a constant.
●
1. Express the dot product r v as a time derivative().
d
Hint: remember that for two vectors A and B, (AB) =
, (A. B) =
2. What is the distance of the particle from the origin after 4 seconds?
dA
A A·B+ A. d
dB
dt
dt
Transcribed Image Text:A particle starts moving from the origin at time t=0 with the dot production of the position vector and the velocity vector given by rv = k2t, where k is a constant. ● 1. Express the dot product r v as a time derivative(). d Hint: remember that for two vectors A and B, (AB) = , (A. B) = 2. What is the distance of the particle from the origin after 4 seconds? dA A A·B+ A. d dB dt dt
Expert Solution
steps

Step by step

Solved in 3 steps

Blurred answer