A photoelectric experiment with cesium yields stopping potentials of 0.95 V and 0.38 V for A = 435.8 nm and ) = 546.1 nm, respectively. Using only these numbers together with the values of the speed of light (3 × 10° m/s) and the electron charge (e = -1.6 × 10-19 C), find (a) (b) (c) the work function in eV for cesium, the value for Planck's constant h, and the cutoff frequency, below which no electrons would be emitted.

A photoelectric experiment with cesium yields stopping potentials of 0.95 V and 0.38 V for A = 435.8 nm and ) = 546.1 nm, respectively. Using only these numbers together with the values of the speed of light (3 × 10° m/s) and the electron charge (e = -1.6 × 10-19 C), find (a) (b) (c) the work function in eV for cesium, the value for Planck's constant h, and the cutoff frequency, below which no electrons would be emitted.