A pipeline needs to be built to link two points A and B on either side of a river. B is 12km downstream of A. The project plans to lay the pipeline across the river to a point C and then follow the river on dry land to B as shown in the diagram below: 1. 200 m 12 km To cross the river a tunnel has to be built. It costs more to lay the pipeline under the river rather than on dry land. It costs £1.5 million per km to build the pipeline on dry land. The cost of building the pipeline through the tunnel is estimated to be 1.2 times the cost of building on dry land. Before making a decision on whether to go ahead with the project, it is necessary to determine the length of the tunnel that minimises cost. (i) Show that the cost (in millions of pounds) of the project is C = 1.8 vx2 + 0.04 + 1.5 ( 12 – x).

A pipeline needs to be built to link two points A and B on either side of a river. B is 12km downstream of A. The project plans to lay the pipeline across the river to a point C and then follow the river on dry land to B as shown in the diagram below: 1. 200 m 12 km To cross the river a tunnel has to be built. It costs more to lay the pipeline under the river rather than on dry land. It costs £1.5 million per km to build the pipeline on dry land. The cost of building the pipeline through the tunnel is estimated to be 1.2 times the cost of building on dry land. Before making a decision on whether to go ahead with the project, it is necessary to determine the length of the tunnel that minimises cost. (i) Show that the cost (in millions of pounds) of the project is C = 1.8 vx2 + 0.04 + 1.5 ( 12 – x).

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Description: Need help to understand the question A pipeline needs to be built to link two points A and B on either side of a river.B is 12km downstream of A. The project plans to lay the pipeline across theriver to a point C and then follow the river on dry land

Intermediate Algebra

19th Edition

ISBN:9780998625720

Author:Lynn Marecek

Publisher:Lynn Marecek

Chapter2: Solving Linear Equations

Section2.4: Solve Mixture And Uniform Motion Applications

Problem 291E: Sarah wants to arrive at her friend’s wedding at 3:00. The distance from Sarah’s house to the...

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