A plaintext ‘ATTACT THE SHIP PASSING SUNDA STRAIGHT’ is sent and ecrypted using Vigenere with the key 'ahmadhelmi' which is followed by Hill Cipher using the key 2 -1 3 5 2 1 1 3 -3 - Write the encryption and decryption process and the results in detail!
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A plaintext ‘ATTACT THE SHIP PASSING SUNDA STRAIGHT’ is sent and ecrypted using
Vigenere with the key 'ahmadhelmi' which is followed by Hill Cipher using the key
2 -1 3
5 2 1
1 3 -3
- Write the encryption and decryption process and the results in detail!
Step by step
Solved in 2 steps with 3 images
- 11. In OFB Transmission errors do not propagate: only the current ciphertext is affected, since keys are generated “locally”. i) True ii) False6. You intercept the ciphertext ’ JVCPK’. Knowing that the ciphertext was obtained using a Shift Cipher, determine the key k that was used. What is the enciphering formula? What is the deciphering formula? Hint: The trick is to try all the possible keys until you find one that gives a familiar word.... Show your workThe coded message that follows is an encrypted message from Brutus to the Roman Senate. It was produced using the Caesar cipher method, using a key-value of +5: OHWV GR MXOLXV RQ PRQGDB PDUFK 48 GUHVV: WRJD FDVXDO (EBRG) True False The standard format for an e-mail address is USER NAME@DOMAIN NAME. True False
- q11- "Moral" has been encrypted with Caesar cipher to "Rtwfq". Find the key to this Caesar cipher? Hint: Convert the numbers into mod 26 range. (0,1,2,3,.... 25) a- 31 mod 26 b- 34 mod 26 c- 26 mod 26 d- NoneWe know that the size of the key in Data Encryption Standard (DES) is 64 bits, assume for padding we just add 0 atthe end of the plaintext (the original message), what is the result of padding for thefollowing text? At first replace the “YYY” with the first 3 letters of your name or familythen calculate the padding (show the result in hexadecimal format):“YYYComputerSecurity”Decrypt the following ciphertext using frequency analysis, and explain the entire process. Even if you don’t achieve the complete decryption, you can still get full credit as long as you properly demonstrate the methodology. “FX IWBBJX PB NB PB PWX GBBD. VSP FWO, JBGX JRO, PWX GBBD? FWO IWBBJX PWUJ RJ BSA NBRK? RDL PWXO GRO FXKK RJM FWO IKUGV PWX WUNWXJP GBSDPRUD? FWO, 35 OXRAJ RNB, EKO PWX RPKRDPUI? FWO LBXJ AUIX CKRO PXQRJ? FX IWBBJX PB NB PB PWX GBBD UD PWUJ LXIRLX RDL LB PWX BPWXA PWUDNJ, DBP VXIRSJX PWXO RAX XRJO, VSP VXIRSJX PWXO RAX WRAL, VXIRSJX PWRP NBRK FUKK JXATX PB BANRDUZX RDL GXRJSAX PWX VXJP BE BSA XDXANUXJ RDL JMUKKJ, VXIRSJX PWRP IWRKKXDNX UJ BDX PWRP FX RAX FUKKUDN PB RIIXCP, BDX FX RAX SDFUKKUDN PB CBJPCBDX, RDL BDX FWUIW FX UDPXDL PB FUD, RDL PWX BPWXAJ, PBB.”
- The coded message that follows is an encrypted message from Brutus to the Roman Senate. It was produced using the Caesar cipher method, using a key-value of +5: OHWV GR MXOLXV RQ PRQGDB PDUFK 48 GUHVV: WRJD FDVXDO (EBRG) True FalseWrite the solution in detail:A) Encrypt the following message using poly-alphabetic cipher:Plaintext: “HELLO WORLD”Key:Shift the first letter three positions to its rightShift the second letter five positions to its rightShift the third letter seven-position to its left B) Using the same key, decrypt the following text:Cipher text= “vjv xwb wd”54. A message "COMPUTERNETWORK" encrypted (ignore quotes) using columnar transposition cipher with a key "LAYER". The encrypted message is : a. CTTOEWMROPNRUEK b. MROUEKCTTPNROEW c. OEWPNRCTTUEKMRO d. UEKPNRMROOEWCTT
- Using the transposition cipher technique, decrypt the following message: EENRE*ERTEA*GRS The message was encrypted using a grid of 3 by 5 (3 rows, 5 columns) by spiraling inward from the top right of the grid moving clockwise.Using Vigenère Cipher, decrypt the given cipher text “PNDSRX DLSCWXT” and find its plaintext. The secret key is “basket”. Consider the space between the two words of cipher text.Consider the plaintext PLAINCIPHERTEST , arrange it to 3*5 matrix and rearrange R1, TO R3,R2, TO R3,C1 TO C2. what will be the cipher text produced