a) Find the y and z component of magnetic dipole moment at the minimum potential energy position? b) How much external energy is required to keep the dipole in maximum potential energy position? (FInd : absolute value of external energy) A planet with earth like magnetic field can be considered as a bar magnet. Suppose, we have such a bar magnet. We will treat it a magnetic dipole. Itsdipole moment is given by the i = Hyj+µzk which remains unchanged without the application of external magnetic field. Suppose, a uniformmagnetic field given by, B = ((-40.0) j+ (-35.0) k) × 10º Tesla. Some neutron stars can generate such intense magnetic field. When thismagnetic field is applied, the bar magnet starts to rotate. At some instant during rotation, consider it as "position 1" of the dipole, it's torque is7 = (2055.2023883969796) × 10290.0 ¿ N - m and potential energy is U = -2890.651854292964 × 1020.0 J.

Here the earth is considered as a Bar magnet. The dipole moment is given by μ→=μy j+μz kThe…

A planet with earth like magnetic field can be considered as a bar magnet. Suppose, we have such a bar magnet. We will treat it a magnetic dipole. dipole moment is given by the ji = Hyj+µzk which remains unchanged without the application of external magnetic field. Suppose, a uniform magnetic field given by, B = ((-40.0) j+ (–35.0) k) × 10º Tesla. Some neutron stars can generate such intense magnetic field. When this magnetic field is applied, the bar magnet starts to rotate. At some instant during rotation, consider it as "position 1" of the dipole, it's torque is T = (2055.2023883969796) × 1029.0 ¿ N · m and potential energy is U = –2890.651854292964 × 1029.0 J.

A planet with earth like magnetic field can be considered as a bar magnet. Suppose, we have such a bar magnet. We will treat it a magnetic dipole. dipole moment is given by the ji = Hyj+µzk which remains unchanged without the application of external magnetic field. Suppose, a uniform magnetic field given by, B = ((-40.0) j+ (–35.0) k) × 10º Tesla. Some neutron stars can generate such intense magnetic field. When this magnetic field is applied, the bar magnet starts to rotate. At some instant during rotation, consider it as "position 1" of the dipole, it's torque is T = (2055.2023883969796) × 1029.0 ¿ N · m and potential energy is U = –2890.651854292964 × 1029.0 J.