A population of bacteria has 1175 bacteria in its starting population. The half-ife of this particular type of bacteria is 14 days. (This means that every 14 days the population decreases by haif.) Write a function B(d) that represents the amount of bacteria B in the population after d days. B(d) = 1175(14/365^365d In this and every exponential problem, if you use decimals you must use 7 or 8 decimal places. If that doesn't work you will have to use fractions.

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter7: Exponents And Exponential Functions
Section7.8: Transforming Exponential Expressions
Problem 1CYU
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A population of bacteria has 1175 bacteria in its starting population. The half-life of this particular type of bacteria is 14 days. (This means that every 14
days the population decreases by haif.) Write a function B(d) that represents the amount of bacteria B in the population after d days.
B(d) = 1175(14/365)^365d
In this and every exponential problem, if you use decimals you must use 7 or 8 decimal places. If that doesn't work you will have to use fractions.
Transcribed Image Text:A population of bacteria has 1175 bacteria in its starting population. The half-life of this particular type of bacteria is 14 days. (This means that every 14 days the population decreases by haif.) Write a function B(d) that represents the amount of bacteria B in the population after d days. B(d) = 1175(14/365)^365d In this and every exponential problem, if you use decimals you must use 7 or 8 decimal places. If that doesn't work you will have to use fractions.
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