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A probability distribution has equal mean and median, and P(88 < X < 96) = 0.68, P(84< X <100) = 0.95, P(80< X <104) = 0.997. Part A: How would you classify this distribution? Why? Part B: Determine the mean and standard deviation of this distribution. Part C: Calculate and sketch the following situation: P(64< X <110). Part D: Calculate and sketch the following situation: P(X < c) = 0.1998

A probability distribution has equal mean and median, and P(88 < X < 96) = 0.68, P(84< X <100) = 0.95, P(80< X <104) = 0.997. Part A: How would you classify this distribution? Why? Part B: Determine the mean and standard deviation of this distribution. Part C: Calculate and sketch the following situation: P(64< X <110). Part D: Calculate and sketch the following situation: P(X < c) = 0.1998

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.4: Distributions Of Data
Problem 19PFA
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A probability distribution has equal mean and median, and P(88 < X< 96) = 0.68, P(84< X <100) = 0.95, P(80< X <104) = 0.997. Part A: How would you classify this distribution? Why? Part B: Determine the mean and standard deviation of this distribution. Part C: Calculate and sketch the following situation: P(64< X <110). Part D: Calculate and sketch the following situation: P(X < c) = 0.1998
Transcribed Image Text:A probability distribution has equal mean and median, and P(88 < X< 96) = 0.68, P(84< X <100) = 0.95, P(80< X <104) = 0.997. Part A: How would you classify this distribution? Why? Part B: Determine the mean and standard deviation of this distribution. Part C: Calculate and sketch the following situation: P(64< X <110). Part D: Calculate and sketch the following situation: P(X < c) = 0.1998
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