A productivity formula for a student's performance on a basket-weaving examination is g = 12tx – 0.21² – 10x² (t < 10), where g is the score the student can expect to obtain, t is the number of hours of study for the examination, and x is the student's grade-point average. (a) For how long should a student with a 3.0 grade-point average study to score 81 on the examination? (Round your answer to two decimal places.) hr dt for a student who earns a score of 81, evaluate it when x = 3.0. (Round your answer to four decimal places.) dx (b) Find dt hr per grade point dx Interpret the result. Note that this is positive, implying that the required study hour v ---Select--- the grade point average increases. This means that, for a 3.0 student who scores 81 on the examination, a 1.0 grade point is worth hours mor increases ther words, the higher your GPA, the harder you have to study for the test!

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ISBN:9781305115545
Author:James Stewart, Lothar Redlin, Saleem Watson
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Chapter3: Polynomial And Rational Functions
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A productivity formula for a student's performance on a basket-weaving examination is
g = 12tx – 0.2t2 – 10x2
(t < 10),
where g is the score the student can expect to obtain, t is the number of hours of study for the examination, and x is the student's grade-point average.
(a) For how long should a student with a 3.0 grade-point average study to score 81 on the examination? (Round your answer to two decimal places.)
t =
hr
(b) Find
dt
for a student who earns a score of 81, evaluate it when x = 3.0. (Round your answer to four decimal places.)
dx
dt
hr per grade point
dx
Interpret the result.
Note that this is positive, implying that the required study hour v ---Select---
the grade point average increases. This means that, for a 3.0 student who scores 81 on the
ther words, the higher your GPA, the harder you have to study for the test!
examination, a 1.0 grade point is worth
hours mor
increases
decreases
Transcribed Image Text:A productivity formula for a student's performance on a basket-weaving examination is g = 12tx – 0.2t2 – 10x2 (t < 10), where g is the score the student can expect to obtain, t is the number of hours of study for the examination, and x is the student's grade-point average. (a) For how long should a student with a 3.0 grade-point average study to score 81 on the examination? (Round your answer to two decimal places.) t = hr (b) Find dt for a student who earns a score of 81, evaluate it when x = 3.0. (Round your answer to four decimal places.) dx dt hr per grade point dx Interpret the result. Note that this is positive, implying that the required study hour v ---Select--- the grade point average increases. This means that, for a 3.0 student who scores 81 on the ther words, the higher your GPA, the harder you have to study for the test! examination, a 1.0 grade point is worth hours mor increases decreases
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