= A= putting A = (-1). 5 -2 -5 1 a= 3, 5 -2 -5 1 a b C d 3 5 7 d b= 5, C= 7, d=l -2 7 1 2 12 -3 d 1 -2 -2 -7 7 12 - -3 1 -2 9 5 -2 -5 1 0 0 1 Am d 3 3 2 7 1 -2 2 -19 6 29 0 19 29 We get, 1₂²=2-9 33²=33-4 cu = 44-44 ( Expanding with respect to fourt row)

Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter2: Systems Of Linear Equations
Section2.4: Applications
Problem 29EQ
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How did you get it? Pls check the circle. find the determinant!
=
A =
putting
||
A -
(-).
5
-2
-5
1
G= 3,
5
-2
-5
1
a
b
C
d
3
5
Tt
6= 5, C= 7, del
5 -2
-2
-5
1
*
4
-2
12
12
-2
0
-3
- 2
1
- 3
—
-7
3
m d
3
2
0
1
1
-2
2
-2
ง
1
9
น
2
– 9
6
25
0
ๆ
e get,
We
C = 9 - 9
S - G - C
C = Cy - 4G
( Expanding
with respect to
fourth row)
Transcribed Image Text:= A = putting || A - (-). 5 -2 -5 1 G= 3, 5 -2 -5 1 a b C d 3 5 Tt 6= 5, C= 7, del 5 -2 -2 -5 1 * 4 -2 12 12 -2 0 -3 - 2 1 - 3 — -7 3 m d 3 2 0 1 1 -2 2 -2 ง 1 9 น 2 – 9 6 25 0 ๆ e get, We C = 9 - 9 S - G - C C = Cy - 4G ( Expanding with respect to fourth row)
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