q7 Given the power series2 (n - 3) A xn – 5)n = 2Use the technique that we covered in this unit to Shift the Iindex of the Power Series so that the exponent of the power series issimplified.0000(A)2 (n - 3) A x(" - 5) becomes2 (R + 5) A (R + 5) **n = 2R = -3Bn = 22 (n - 3) A x(* - $) becomesE (R + 2) A (R + 5) *R = -3©E (R + 8) A (a - 5) *2 (n - 3) A x" - 5) becomesn = 2R = 70000OD2 (n - 3) A x(a – 5)becomes E (R - 8) A (r – 5) **n = 2R = 000e 2 (n - 3) A x" - 5) becomesE (R + 2) A (R + 5)En = 2R = 200F2 (n - 3) A x" - 5) becomesΣ (R-3 )A, x'n = 2R = 2

Here, the given series is: ∑n=2∞(n-3)Anxn-5...(1)

A (R - 5) Given the power series E (n - 3) A, xla - 5) n = 2 Use the technique that we covered in this unit to Shift the Index of the Power Series so that the exponent of the power series is simplified. A E (n - 3) A xla - 5) n = 2 x(a - 5) (R + 5) A (r + 5) ** becomes R= -3 E (n- 3) A, xla - 5) becomes E (R + 2) A (r + 5) ** R = -3 n = 2 © E (n - 3) A x" - 5) becomes £ (R + 8) A (R - 5) n = 2 R = 7 OE (n- 3) A, xl* - 5) becomes E (R - 8) A (r – 5) ** n = 2 R= 0 00 E (n- 3) A, xla - 5) becomes E (R+ 2) A (R + 5) ** n = 2 R= 2 E (n- 3) A x - 5) becomes (R - 3) A, xe

A (R - 5) Given the power series E (n - 3) A, xla - 5) n = 2 Use the technique that we covered in this unit to Shift the Index of the Power Series so that the exponent of the power series is simplified. A E (n - 3) A xla - 5) n = 2 x(a - 5) (R + 5) A (r + 5) becomes R= -3 E (n- 3) A, xla - 5) becomes E (R + 2) A (r + 5) R = -3 n = 2 © E (n - 3) A x" - 5) becomes £ (R + 8) A (R - 5) n = 2 R = 7 OE (n- 3) A, xl* - 5) becomes E (R - 8) A (r – 5) n = 2 R= 0 00 E (n- 3) A, xla - 5) becomes E (R+ 2) A (R + 5) n = 2 R= 2 E (n- 3) A x - 5) becomes (R - 3) A, xe

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter10: Sequences, Series, And Probability

Section10.2: Arithmetic Sequences

Problem 68E

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