A rain gutter is to be constructed from a metal sheet of width 54 cm by bending up one-third of the sheet on each side through an angle 8. 18 ст 18 ст 18 ст (a) Show that the cross-sectional area of the gutter is modeled by the function A(6) = 324 sin(e) + 324 sin(6) cos(8).

Algebra and Trigonometry (MindTap Course List)
4th Edition
ISBN:9781305071742
Author:James Stewart, Lothar Redlin, Saleem Watson
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Chapter5: Trigonometric Functions: Right Triangle Approach
Section5.4: Inverse Trigonometric Functions And Right Triangles
Problem 1E: For a function to have an inverse, it must be ___________. To define the inverse sine function, we...
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I just need help with part a and c

A graphing calculator is recommended.
A rain gutter is to be constructed from a metal sheet of width 54 cm by bending up one-third of the sheet on each side through an angle 8.
18 сm
18 cm
18 ст
Show that the cross-sectional area of the gutter is modeled by the function
A(8) = 324 sin(6) + 324 sin(6) cos(8).
This answer has not been graded yet.
(b) Graph the function A for 0s e s a/2.
A(6)
A(6)
600
600
500
500
400
400
300
300
200
200
100
100
0.5
1.0
1.5
0.5
1.0
1.5
A(6)
A(6)
600
600
500
500
400
400
300
300
200
200
100
100
0.5
1.0
1.5
0.5
1.0
1.5
(c) For what angle 6 is the largest cross-sectional area achieved? (Round your answer to two decimal places.)
Transcribed Image Text:A graphing calculator is recommended. A rain gutter is to be constructed from a metal sheet of width 54 cm by bending up one-third of the sheet on each side through an angle 8. 18 сm 18 cm 18 ст Show that the cross-sectional area of the gutter is modeled by the function A(8) = 324 sin(6) + 324 sin(6) cos(8). This answer has not been graded yet. (b) Graph the function A for 0s e s a/2. A(6) A(6) 600 600 500 500 400 400 300 300 200 200 100 100 0.5 1.0 1.5 0.5 1.0 1.5 A(6) A(6) 600 600 500 500 400 400 300 300 200 200 100 100 0.5 1.0 1.5 0.5 1.0 1.5 (c) For what angle 6 is the largest cross-sectional area achieved? (Round your answer to two decimal places.)
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