A random sample of 17 chemists from Washington state shows an average salary of $49093 with a standard deviation of $536. A random sample of 15 chemists from Florida state shows an average salary of $45101 with a standard deviation of $631. A chemist that has worked in both states believes that chemists in Washington make a different amount than chemists in Florida. At a=0.01 is this chemist correct? Let Washington be sample 1 and Florida be sample 2. The correct hypotheses are: O Ho:µ1 < H2 HA: H1 > µ2(claim) Ο H: μι > μ2 HA: H1 < µ2(claim) O Ho:µ1 = µ2 HA: H1 + H2(claim) Since the level of significance is 0.01 the critical value is 2.766 and -2.766 The test statistic is: (round to 3 places) The p-value is: (round to 3 places) The decision can be made to: O reject Ho O do not reject Ho The final conclusion is that: O There is enough evidence to reject the claim that chemists in Washington make a different amount than chemists in Florida. O There is not enough evidence to reject the claim that chemists in Washington make a different amount than chemists in Florida. O There is enough evidence to support the claim that chemists in Washington make a different amount than chemists in Florida. O There is not enough evidence to support the claim that chemists in Washington make a different amount than chemists in Florida.

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A random sample of 17 chemists from Washington state shows an average salary of $49093 with a standard
deviation of $536. A random sample of 15 chemists from Florida state shows an average salary of $45101
with a standard deviation of $631. A chemist that has worked in both states believes that chemists in
Washington make a different amount than chemists in Florida. At a=0.01 is this chemist correct? Let
Washington be sample 1 and Florida be sample 2.
The correct hypotheses are:
O Ho: µ1 < µ2
HA: H1 > l2(Cclaim)
O Ho: H1 2 µ2
HA: H1 < µ2(claim)
O Ho: µ1 = 2
HA: 41 7 H2(claim)
Since the level of significance is 0.01 the critical value is 2.766 and -2.766
The test statistic is:
(round to 3 places)
The p-value is:
(round to 3 places)
The decision can be made to:
O reject Ho
O do not reject Ho
The final conclusion is that:
There is enough evidence to reject the claim that chemists in Washington make a different amount
than chemists in Florida.
O There is not enough evidence to reject the claim that chemists in Washington make a different
amount than chemists in Florida.
O There is enough evidence to support the claim that chemists in Washington make a different amount
than chemists in Florida.
O There is not enough evidence to support the claim that chemists in Washington make a different
amount than chemists in Florida.
Transcribed Image Text:A random sample of 17 chemists from Washington state shows an average salary of $49093 with a standard deviation of $536. A random sample of 15 chemists from Florida state shows an average salary of $45101 with a standard deviation of $631. A chemist that has worked in both states believes that chemists in Washington make a different amount than chemists in Florida. At a=0.01 is this chemist correct? Let Washington be sample 1 and Florida be sample 2. The correct hypotheses are: O Ho: µ1 < µ2 HA: H1 > l2(Cclaim) O Ho: H1 2 µ2 HA: H1 < µ2(claim) O Ho: µ1 = 2 HA: 41 7 H2(claim) Since the level of significance is 0.01 the critical value is 2.766 and -2.766 The test statistic is: (round to 3 places) The p-value is: (round to 3 places) The decision can be made to: O reject Ho O do not reject Ho The final conclusion is that: There is enough evidence to reject the claim that chemists in Washington make a different amount than chemists in Florida. O There is not enough evidence to reject the claim that chemists in Washington make a different amount than chemists in Florida. O There is enough evidence to support the claim that chemists in Washington make a different amount than chemists in Florida. O There is not enough evidence to support the claim that chemists in Washington make a different amount than chemists in Florida.
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