A rectangle is growing such that the length of a rectangle is 5t + 4 and its height is t, where t is time in seconds and the dimensions are in inches. Find the rate of change of area, A, with respect to time. O A) da = t* (16 + 25t) square inches/second O B) dA = t° (16 + 25t) square inches/second %3D O C) dA = t³ (16 + 20t) square inches/second O D) dA = t*(12+ 25t) square inches/second O E) dA = t° (25t + 4) square inches/second

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