A rectangular tied braced column is reinforced with 6-28mm bars as shown in the figure below. Check the adequacy of the column for the following gravity loads; - Service dead load = 1050kN Service live load = 850 kN Service dead load moment = Service live load moment = - } At eccentricity of 40mm 39 kN-m 27 kN-m
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- A rectangular tied braced column is reinforced with 6-28mm bars as shown in the figure below. Check the adequacy of the column for the following gravity loads: - - - - - - Service dead load = 1050kN Service live load = 850 kN Service dead load moment = 39 kN-m Service live load moment = 27 kN-m top=bott. = 1.0 40 lu = 5.0m f = 27.6 N/mm², fy = 414 N/mm² axis of bending 500mm Ties 10mm@300c/c } 350mm At eccentricity of 40mm P M +40 + 500mm MU +40- P Top end Bott. end1. A steel column 10 m long is fabricated from a cover plate and C section arranged as shown. Determine the safe compressive load. Fy = 248 MPa, E= 200 GPa. Use AISC/NSCP Specs. 450 mm -cover plate 'I 12 mm y2 IP d2 10 m C 310 x 37 A = 4720 mm? d = 305 mm bf = 77 mm tf = 12.7 mm tw = 9.8 mm C 310 X 37 a) Both ends of column are fixed b) Both ends of column are hinged c) One end fixed, the other end hinged Use design values of k. tw d=305- Ix = 59.9x10° mm ly = 1.85x10° mm x = 17.1 mm x=17.1Answer the following for the section at Point D Only Calculate the distributed load "w" that: Will cause the section crack Will cause the reinforcement to yield. Material Properties: F'c = 5000 psi Fy = 60000 psi Es = 29000000 psi Ln = 27 ft L wl₂² 16 wl,² 14 CD L wl,2 vl₁² 10 11 win² 16 h: 28 in A=4 in² b=14 in n d: 25 in
- Grath fas A cantlever AB o erath lm carries a from klev. uniformly distributed load, wNm fe fired end A to the free end B. Te the cantilever Consista a horizontal thicknees lomm and with 120mm as shown in fhe below, plars plate4 figure calculate the total permiseiblé diafribte load,wif the meximum bending Stress is not exceeding 10OMH/mt. Ignore the grore te weight a the tlefe Im 120mmDetermine the safe load of the column section shown, if it has a yield strength of 25 MPa. E = 200000 MPa. Use NSCP Specifications. Fyz248 mpa Properties of Channel Section d = 305 mm t₂ = 7.2 mm A = 3929 mm² t₁ = 12.7 mm Ix=53.7 x 10mm¹ x = 117 mm Properties of W 460 x 74 A = 9450 mm² b = 190 mm ly= 1.61 x 10 mm x = 17.7 mm tw = 9.0 mm rx = 188 mm ry = 41.9 mm d = 457 mm tr = 14.5 mm Ix = 333 x 10 mm Iy = 16.6 x 10mm* 7.21 When the height of column is 6 m. When the height of column is 10 m. Assume K= 1.0 457 CIVIL ENGINEERING- STEEL DESIGNThe below figure represents a section of a pre- stressed beam. For a no-tension design where a is the permissible stress in concrete, the total moment carrying capacity is (a) (c) d/2 bd² 6 d/2 bd²oc 3 -b- (b) (d) bd² oc 4 bd²a 12
- A W350x90 girder 8m long carries a concentrated dead load, P at every quarter points and a uniform dead load of 5 kN/m (including dead weight) amd a uniform live load of 7.2 kN/m. CIVIL ENGINEERING STEEL Properties: A = 11,500 mm² tw = 10 mm tf = 16 mm mm Ix=1119.7 x 10 mm* Allowable Stresses: Fb = 0.66 Fy d = 350 mm bf = 250 mm tf = 16 mm Fv = 0.40 Fy a.) Determine P base on Flexure. b.) Determine P base on Shear. b.) Determine P base on Deflection. DESIGN Sallow=1/3601. For the Pratt bridge truss and the loading shown below, determine the average normal stress in member BE, knowing that the cross-sectional area of that member is 60 in². NN K 12-12--12--12--| 50 lips 50 kips 50. ips Figure 1 G xfoneA square hollow steel strut if thickness 10mm is pin connected to two connector plates of thickness, 12mm. The connector plates are welded to the base plate of thickness, 12mm. The base plate is fastened to te concrete base by 4-16mm diameter anchor bolts. The diameter of the pin is 16mm. Which of the following most nearly gives the shearing stress in the anchor bolts? Choices 150.00 MPa 59.68 MPa 51.69 MPa 119.37 MPa
- ... Determine the nominal axial compressive strength, Pn for the following cases: a. L= 15 ft b. L = 20 ft Note: Pinned both end support W10 × 33 A992 steel r = 1.94 in E = 29000 ksi Fy = 50ksi L a) Blank 1 b) Blank 2 Blank 1 Add your answer Blank 2 Add your answerin 21- ő A steel beam is reinforced by three steel rods. The modulous of elasticity for concrete is 20Gpa and for steel is 200Gpa. Maximum allowable stress for concrete is 9.45Mpa and for steel is 140Mpa. Calculate the largest allowable positive WBT bending moment in the beam. иа mo maod motinu od o boblow need sved Ha bus 400mm aidT (alonnerlo ert to rigiow stongi)/4000E of Trup 200-0 signs or botuesom sWnworla es berloss M bris V zsra erli owob stiW maod sdi to mergeib insm brol bus borlism tuo sallimill nollor 10 nige over on The modulus of elasticity for concrete is 20Gpa and for the steel is 200 Gpa. Allowable stress for concrete is 9Mpa and for steel is 140Mpa. Calculate the maxium allowable bending momemt that can be applied per metal rod of the concrete slab. 150mm 200mm D=16mm 140 mm -22mm Diameter TOPABA t 50mm T 140 mm 140 mm 140 mmUse 2015 NSCP. A compression member shown below with Fy = 50 ksi 30′ W12 x 87 A992 steel 1. Which of the following most nearly gives the value of critical buckling stress in ksi? 2. Which of the following most nearly gives the nominal strength in kips? 3. Considering ASD. Which of the following most nearly gives the allowable strength in kips? 4. Considering LRFD. Which of the following most nearly gives the design strength in kips?