a) Refer to Figure #1. A wagon is moving in a straight line with constant acceleration a, and its kinematics is measured with respect to inertial coordinates (X1, Y1). A ball inside the wagon is acted upon by a force F (components F, and F,) and gravity force Mg. The coordinate (X2, Y2) is moving with the wagon. Detemine the acceleration of the ball measured in the (X2, Y2) coordinate frame. In other words, compute the acceleration of the ball relative to the wagon. Y,A (M X, ► x, Figure 1 (a) Answer: a(M/W)x = Fx/M - ax; a(M/W)y = Fy/M – g

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Show transcribed image text a) Refer to Figure #1. A wagon is moving in a straight line with constant acceleration ax and its kinematics is measured with respect to inertial coordinates (X1, Y1). A ball inside the wagon is acted upon by a force F (components F7 and Fy) and gravity force Mg. The coordinate (x2. Y2) is moving with the wagon. Determine the acceleration of the ball measured in the (X2. Y2) coordinate frame. In other words, compute the acceleration of the ball relative to the wagon.

(a) Answer: a(M/W)x = FX/M - ax; a(M/W)y = Fy/M - g

a) Refer to Figure #1. A wagon is moving in a straight line with constant acceleration a, and its
kinematics is measured with respect to inertial coordinates (X1, Y1). A ball inside the wagon is
acted upon by a force F (components F, and F,) and gravity force Mg. The coordinate (X2, Y2)
is moving with the wagon. Detemine the acceleration of the ball measured in the (X2, Y2)
coordinate frame. In other words, compute the acceleration of the ball relative to the wagon.
Y,A
(M
X,
► x,
Figure 1
(a) Answer: a(M/W)x = Fx/M - ax; a(M/W)y = Fy/M – g
Transcribed Image Text:a) Refer to Figure #1. A wagon is moving in a straight line with constant acceleration a, and its kinematics is measured with respect to inertial coordinates (X1, Y1). A ball inside the wagon is acted upon by a force F (components F, and F,) and gravity force Mg. The coordinate (X2, Y2) is moving with the wagon. Detemine the acceleration of the ball measured in the (X2, Y2) coordinate frame. In other words, compute the acceleration of the ball relative to the wagon. Y,A (M X, ► x, Figure 1 (a) Answer: a(M/W)x = Fx/M - ax; a(M/W)y = Fy/M – g
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From figure,The force acting in the ball along x-direction is Fxand Force acting along y-direction is FyWhereas, Acceleration of wagon along x-direction is ax and there will be acceleration due to gravity in the ball along y-direction.Hence, Net force acting on the ball along x-direction , we will subtract relative movementthen,abx=FxM-ax

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