I.A relationship between (y-2) and(x – 1)is given by (y- 2) = a b(x-1).With a suitable lincar relationship between(y - 2) and (x– 1), the intercept of the%3Dstraight line in the axis oflog(y- 2) isA log bB 2 log bC 2 log a/D log a

relationship between (y-2) and (x-1) is (y-2) = ab(x-1) So we will find the solution using logarithm…

A relationship between (y – 2) and (x- 1)is given by (y – 2) = a b(x-1). With a suitable lincar relationship between (y - 2) and (x- 1), the intereept of the straight line in the axis of log(y – 2) is %3D A log b B 2 log b C 2log a /D log a

A relationship between (y – 2) and (x- 1)is given by (y – 2) = a b(x-1). With a suitable lincar relationship between (y - 2) and (x- 1), the intereept of the straight line in the axis of log(y – 2) is %3D A log b B 2 log b C 2log a /D log a

College Algebra

1st Edition

ISBN:9781938168383

Author:Jay Abramson

Publisher:Jay Abramson

Chapter6: Exponential And Logarithmic Functions

Section6.1: Exponential Functions

Problem 60SE: The formula for the amount A in an investmentaccount with a nominal interest rate r at any timet is...

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Question

I.
A relationship between (y-2) and
(x – 1)is given by (y- 2) = a b(x-1).
With a suitable lincar relationship between
(y - 2) and (x– 1), the intercept of the
%3D
straight line in the axis of
log(y- 2) is
A log b
B 2 log b
C 2 log a
/D log a

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