A research lab grows a type of bacterium in culture in a circular region. The radius of the circle, measured in 6 centimeters, is given by r(t) = 5 - 1²2+3 where t is time measured in hours passed since a circle of a 1cm radius of the bacterium was put into the culture. Express the area, A (t), of the bacteria as a function of time, and find the approximate area of the bacterial culture in 4 hours. A A(t) B A(t) = n(5- 6 1² +3 A(t) = 2n(5- 6 t²+3 6 ⒸA(₁) = 4√(3 - 12/²+3) 5 and Area after 4 hours = 14.72, cm² and Area after 4 hours = 29.43, cm² and Area after 4 hours = 68.93, cm² 6 2 ⒸA(1) = 24 (5 - 72 043) ² D t² +3 and Area after 4 hours = 137.86, cm²
A research lab grows a type of bacterium in culture in a circular region. The radius of the circle, measured in 6 centimeters, is given by r(t) = 5 - 1²2+3 where t is time measured in hours passed since a circle of a 1cm radius of the bacterium was put into the culture. Express the area, A (t), of the bacteria as a function of time, and find the approximate area of the bacterial culture in 4 hours. A A(t) B A(t) = n(5- 6 1² +3 A(t) = 2n(5- 6 t²+3 6 ⒸA(₁) = 4√(3 - 12/²+3) 5 and Area after 4 hours = 14.72, cm² and Area after 4 hours = 29.43, cm² and Area after 4 hours = 68.93, cm² 6 2 ⒸA(1) = 24 (5 - 72 043) ² D t² +3 and Area after 4 hours = 137.86, cm²
Chapter3: Functions
Section3.4: Composition Of Functions
Problem 94SE: A forest fire leaves behind an area of grass burned in an expanding circular pattern. If the radius...
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Transcribed Image Text:6
centimeters, is given by r(t) = 5 -
t² +3
A research lab grows a type of bacterium in culture in a circular region. The radius of the circle, measured in
where t is time measured in hours passed since a circle of a 1cm
radius of the bacterium was put into the culture. Express the area, A (t), of the bacteria as a function of
time, and find the approximate area of the bacterial culture in 4 hours.
A
A(t) = n(5-
6
1² +3
B A(t) = 2n(5-
ⒸA(t)
A(1) = x (5
-
-) and Area after 4 hours =
t²+3
6
-) and Area after 4 hours = 29.43, cm²
6 2
1² +3
and Area after 4 hours =
14.72, cm²
6 2
ⒸA(1) = 24 (5 - 7² +43) ²
D)
25
2
t
68.93, cm²
and Area after 4 hours = 137.86, cm²
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