A resistance R, an inductance L, and a capacitance 10 µF are connected in series as shown in the figure below. When an alternating voltage V = 100 cos (500t + 60°) volt is applied to series combination, the resulting current is found to be I = 2 cos (500t + 23.139). Find R, L. 10 µF R ww 100/60* V ĭ1=2/23.13' A

Introductory Circuit Analysis (13th Edition)
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Author:Robert L. Boylestad
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A resistance R, an inductance L, and a capacitance 10 µF are connected
in series as shown in the figure below. When an alternating voltage V =
100 cos (500t + 60°) volt is applied to series combination, the resulting
current is found to be I = 2 cos (500t + 23.13). Find R, L.
10 µF
R
ww
100/60° V
I=2/23.13' A
Transcribed Image Text:A resistance R, an inductance L, and a capacitance 10 µF are connected in series as shown in the figure below. When an alternating voltage V = 100 cos (500t + 60°) volt is applied to series combination, the resulting current is found to be I = 2 cos (500t + 23.13). Find R, L. 10 µF R ww 100/60° V I=2/23.13' A
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