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A rock is dropped from a height of 64ft. Its height above ground at time t seconds later is given by s(t)=−16t2+64 for 0≤t≤2. Find its instantaneous velocity 1 second after it is dropped using the limit definition of a derivative. Do not include units in your answer.

Question

A rock is dropped from a height of 64ft. Its height above ground at time t seconds later is given by s(t)=−16t2+64 for 0≤t≤2. Find its instantaneous velocity 1 second after it is dropped using the limit definition of a derivative. Do not include units in your answer.

check_circleAnswer
Step 1

Instantaneous velocity at t=1 is ds/dt at t=1 , that is s'(1).

Step 2

We substitute s(t) and s(1) in the lim...

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Derivative

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