Question

Asked Sep 30, 2019

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A rock is dropped from a height of 64ft. Its height above ground at time t seconds later is given by s(t)=−16t2+64 for 0≤t≤2. Find its instantaneous velocity 1 second after it is dropped using the limit definition of a derivative. Do not include units in your answer.

Step 1

Consider the model function that represents the height above the ground as s(...

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