I was able to understand the attached problem and have the answer now for mu. So the equation I have is v=150e-6.0788 xMy question, then, is how do we find the TIME to slow the sled to 15 mi/hr ? The answer is supposed to be 35.533 seconds, but I don't know how to get that. Thanks! A rocket sled having an initial speed of 150 mi/hr is slowed by a channel of water. Assume that during thebraking process, the acceleration a is given by a(v)=-mu v², where v is the velocity and mu is a constant.If it requires a distance of 2000 ft to slow the sled to 15 mi/hr, determine the value of mu?

Solution: As per the given data,

A rocket sled having an initial speed of 150 mi/hr is slowed by a channel of water. Assume that during the braking process, the acceleration a is given by a(v)=-mu v , where v is the velocity and mu is a constant. If it requires a distance of 2000 ft to slow the sled to 15 mi/hr, determine the value of mu?

A rocket sled having an initial speed of 150 mi/hr is slowed by a channel of water. Assume that during the braking process, the acceleration a is given by a(v)=-mu v , where v is the velocity and mu is a constant. If it requires a distance of 2000 ft to slow the sled to 15 mi/hr, determine the value of mu?