A rural highway is designed with the following reverse curves. Both curves have the same degree of curvature and radius, i.e., D1=D2 & R1=R2.Calculate:Station of PC, PRC and PT A rural highway is designed with the following reverse curves. Both curves have the same degreeof curvature and radius, i.e., Dı=D2 & R1=R2.Calculate:Station of PC, PRC and PT2100'I,= 59°3000'TLePCPRCLe,PTStation 45+00L= 41°

A rural highway is designed with the following reverse curves. Both curves have the same degree of curvature and radius, i.e., D1=D2 & R1=R2. Calculate: Station of PC, PRC and PT 2100' 59° 3000' Lc PC PRC Le. PT 41° Station 45+00

A rural highway is designed with the following reverse curves. Both curves have the same degree of curvature and radius, i.e., D1=D2 & R1=R2. Calculate: Station of PC, PRC and PT 2100' 59° 3000' Lc PC PRC Le. PT 41° Station 45+00

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: Situation 2] given the following elements of typical compound curve: Angle of Intersection, I = 28°…

A: as per rule i will give only one answer.

Q: A horizontal curve with radius equal to 220m and intersection angle of 126° is to be realigned by…

A: A horizontal curve is a curve that provides a transition between two tangent strips. This curve…

Q: A proposed highway has two tangents of bearings N 45º54’36” E and N 1º22’30” W. The highway design…

A: As per the company guidelines, we are supposed to answer only first three sub-parts. Kindly repost…

Q: A 3% ascending grade meets a descending grade at the vertex at sta. 20+100 and at elevation 120 m.…

A: Here A accending grade meets with descending grade and a symmetrical parabolic curve connecting a…

Q: A simple curve with tangents AV and VE have azimuth of 260-48 and 285-40 respectively. Point B is…

A: A curve with tangent AV having azimuth 260°48' and tangent VE having azimuth 285°40'. Point B is…

Q: Three simple curve are connected to each other such that the first and the second form a compound…

A: Given: Angle of convergence between the second and the third tangent = 15° I1=45°R1=190.986…

Q: A simple curve having a degree of curve of 4° has an angle of intersection of 70°. A line, passing…

A: Solution-The given values ara as below,The degree of curve =4°The angle of…

Q: The perpendicular distance between two parallel tangents of a reversed curve is equal to 8m and has…

Q: Problem no. 2: A compound curve laid on their tangents have the following data: l;= 26°, I;= 17°,…

Q: A horizontal curve with radius equal to 220 m and intersection angle of 126° is to be realigned by…

Q: A plus 2.8 percent grade intersects a minus 5.1 percent grade at station 2+087.224 at an elevation…

A: Pvc station=PVI -L2PVC station =2087.224-1502pVC station=2012.224 →→2+012.224PVT station=PVC +LPVT…

Q: 1. You are traversing along a centerline, (S 45° 00' E), at Station 1+50, you establish a BC, for a…

A: To Determine Length T1 and T2 of the given compound curve.

Q: Two simple curves are connected to form a compound curve 480 meters and 250 meters from the…

Q: A compound curve has a long chord that measures 250 m. The stations of the point of curvature and…

Q: A simple curve has a radius of 80 meters and its angle of intersection is 64 degrees. The curve has…

Q: Given lines AB, BC, and CD, a reversed curve is to connect these three lines thus forming the…

A: Given, D1=4°

Q: 9. Two parallel tangents 20 m apart are to be connected by a reversed curve. The radius of the first…

Q: A horizontal curve with radius of curvature of 1500 ft and a central angle c 59.2 degrees and has…

A: FInd Tangent length T=RtanI2=1500tan59.22=852.12Find length of the curve:L=R×I…

Q: Given lines AB, BC, and CD, a reversed curve is to connect these three lines thus forming the…

Q: A compound curve laid on their tangents has the following data shown below. PI 1 is at 6 + 425.82. I…

A: PI1 = Point of intersection of first curve = 6 + 425.82I1 = Deflection angle of first curve = 22°D1…

Q: Situation 3: An 80 simple curve connecting two tangents that intersect at an angle of 880 is to be…

A: Given, Degree of simple curve, D1=8°Intersection angle=88°Degree of compound curve, D2=3°6º end…

Q: In a rail road layout, the centerline of two parallel fracks are connected with a reversed curve of…

A: long chord of first Curve=2R1sin162=2R1sin80long chord for second curve=2R2sin162=2×290×sin80long…

Q: A parallel reverse curve has a radius of the curve passing through the PC equal to 200m and that of…

Q: a vertical summit curve is having tangents which intersects at point Pl at station 12+615.61 and…

A: This question belongs to subject surveying. In this question we find out the elevation of point…

Q: Two tangents intersecting at point K which is in accessible has an angle of intersection of 30°. Two…

Q: .A +3.00% grade intersects a -2.40 % at station 46+70.00 and elevation 853.48 ft. A 400.00 ft curve…

Q: Problem no. 2: A compound curve laid on their tangents have the following data: I;= 45°, l;= 39°,…

Q: Two parallel roads 29m apart are to be connected by a reversed curve with equal radii at PC and PT.…

A: Given data, Parallel road distance = 29 m Length of common tangent = 169 m To find out the length…

Q: A vertical parabolic curve is designed to pass through three points on the profile of an existing…

Q: The tangents of a spiral curve intersect at an angle of 31.7° at STA 12+598. The degree of the…

A: Given information: Degree of central curve = DE = 5o Length of the spiral curve = LS=54.9 m Radius…

Q: 2. A vertical parabolic curve is designed to pass thru three points on the proffle of an cxisting…

Q: Two tangents adjacent to each other having bearings N65°3O'E and S85°10'E meet at station 11+157.98.…

Q: It is desired to connect two intersecting roadways, the centerlines of which have bearings N 40°30'E…

Q: nd N60°E respectively. If the project Engineer runs the compound curve starting at the point of…

A: Given:- forward tangent bearing=S65E Backward tangent bearing=N60E point of curvature at…

Q: A symmetrical parabolic summit curve connects two grades of +6% and -4%. It is to pass though a…

Q: A simple curve intersects a property line AB. The perpendicular offset distance of point B on a…

A: Curves are customary curves given in the lines of correspondence like streets, rail routes and so on…

Q: A proposed highway has two tangents of bearings N 45°54'36" E and N 1°22'30" W. The highway design…

Q: För a proposed highway curve with a radius of 500.00 meters, the point of curvature (PC) or…

Q: Problem 1: A reverse curve has a radius of the curve passing through the P.C. equal to 200m and that…

Q: A reversed curve is to connect three lines thus forming the center line of a new road. The lines are…

Q: 1. Two roadways AB and CD are to be connected by a reverse curve of common radius, commencing at B…

A: Reverse curves are generally helped to connect two different parallel lines. It is generally helped…

Q: A compound curve laid on their tangents has the following data shown below. PI 1 is at 6 + 425.82. I…

A: Step 1

Q: Problem no. 3: Two simple curves having angles of intersection of the tangents equal to 69° and 42°…

Q: In a compound curve, the line connecting the P.l. at point V and the PC is an angle bisector. VA is…

Q: A simple curve connects two tangent roads AB and BC with bearings N82º40’E and S67º40’E,…

A: "Since you have posted a question with multiple sub-parts, we will solve first three sub parts for…

Q: A horizontal curve with radius equal to 220 m. and intersection angle of 126 ° is to be realigned by…

A: Given:- The radius of the horizontal curve = 220 m The intersection of the curve = 126° The rotation…

Q: The intersection angle of a 10° highway curve is 100°35' and the Point of Intersection (PI) is…

A: Radius=5729.577D=5729.57710=572.9577ftso,Length of tangent is…

Concept explainers

Highway Surveys and Location

Surveying is an operation in the civil engineering domain that requires collecting and identifying data regarding an area of land and topography. The data that is collected can be helped to plan and undertake the construction process. Civil engineers perform surveys to gather three-dimensional information regarding a particular area. Engineers specify several points on the surface of the earth and relationship between points, and the distance and angles between the points are evaluated. The data from this evaluation guides in drawing plans regarding buildings and structures.

Question

A rural highway is designed with the following reverse curves. Both curves have the same degree of curvature and radius, i.e., D1=D2 & R1=R2.
Calculate:
Station of PC, PRC and PT

A rural highway is designed with the following reverse curves. Both curves have the same degree
of curvature and radius, i.e., Dı=D2 & R1=R2.
Calculate:
Station of PC, PRC and PT
2100'
I,= 59°
3000'
T
Le
PC
PRC
Le,
PT
Station 45+00
L= 41°

Expert Solution

Step 1

The given figure is shown below:

Trending now

This is a popular solution!

Step by step

Solved in 10 steps with 1 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

Create a circular curve using this data with a section of a two lane, two highway (2 @ 3.5 m) is to be designed with a circular curve.Sta. PI at 200 + 100.000Design speed = 60 kphIntersection angle = 40 degreesRate of change of acceleration: 0.5 m/sec3
A reversed curve is to connect three lines thus forming the center line of a new road. The lines are AB = 60.2 m, BC = 100.4 m and CD = 100.4 m arranged as shown. Find the length of the common radius of the reverse curve. If station of B is 4+450 m, what is the station of P.C.? If station of B is 4+450 m, what is the station of P.T.?
Show complete solution and drawing. COMPOUND CURVE Problem: Station PT of a Compound Curve Is At 15+480, I1=30˚, I2=36˚, D1=4˚, and D2=5˚. What is the stationing of the vertex of the compound curve?Determine the long chord of the compound curve.
Given a crest curve with slopes p=+3.0% and q= -2.0%, Station of PI= 4+350 and elevation of PI =190.500m., if L =250m, determine the station and elevation of the PC and PT. Calculate the elevations at every 20m station for the length of the curve and locate the station and elevation of the highest point of the curve. Also plot the profile of the curve.
TRAFFIC AND HIGHWAY ENGINEERING:A – 6% grade and a 2% intersect at STA 12+200 whose elevation is at 14.375 m. The twogrades are to be connected by a parabolic curve, 160 m long. Find the elevation of thefirst quarter point on the curve.
a vertical summit curve is having tangents which intersects at point Pl at station 12+615.61 and 134.87 m. The grade for the forward tangent is -6.46%. Station PC is station 12+528.09 and having an elevation of 124.51m. What is the elevation of point A along the curve with Station 12+545.27
Given a sag curve with slopes p= -3.0% and q= 2.0%, Station of PI= 4+350 and elevation of PI =190.500m, if L =250m, determine the station and elevation of the PC and PT. Calculate the elevations at every 20m station and locate the station and elevation of the lowest point of the curve.
A vertical sag parabolic curve has a length of curve of 420 m. from A to B. The back tangent has a slope of −3.2% and the point of intersection of the tangents is at station 7 + 180 with an elevation of 998 m. Find the elevation of point A.
Given a compound curve I -24.1. - 36°while D - 6', D = 4° Compute the length of the common tangent of the curve?
A compound curve is having a common tangent of 104.78 meters long. The central angles made by the common tangent for the first and second simple curve is 18° and 29° respectively. The length of the tangent of the first curve is 30.21 meters and Sta. Pl is 10+180. determine : show solution - length of curve from pc to pt - station pc
If the stationing Pl of spiral curve is at 13 + 184.43 and if R of a simple curve is 273.49m, angle of intersection = 44-degree & Length of spiral= 105m. Determine the stationing at ST.
Given a reversed curre with I1= 20°, I2 =20° and R1= 205 m. The distance between the two parallel tangents is 30.50 m. curve having unequal raduis. Compute the radius of the second curve.