A sample of dry sand is tested in direct shear. The shear box holding the sample has a circular cross section with a diameter of 50 mm. The normal (compressive) load imposed is 210 N. The sample shear when the shear force is 135 N. a) Determine the test normal stress and shear stress at failure. b) Determine the angle of internal friction 0 for this soil c) What is probable condition of the tested sample (dense, loose, etc)?

A sample of dry sand is tested in direct shear. The shear box holding the sample has a circular cross section with a diameter of 50 mm. The normal (compressive) load imposed is 210 N. The sample shear when the shear force is 135 N. a) Determine the test normal stress and shear stress at failure. b) Determine the angle of internal friction 0 for this soil c) What is probable condition of the tested sample (dense, loose, etc)?

Principles of Geotechnical Engineering (MindTap Course List)

9th Edition

ISBN:9781305970939

Author:Braja M. Das, Khaled Sobhan

Publisher:Braja M. Das, Khaled Sobhan

Chapter12: Shear Strength Of Soil

Section: Chapter Questions

Problem 12.20P

See similar textbooks

Similar questions

A sample of dry sand is tested in direct shear. The shear box holding the sample has a circular cross section with a diameter of 50 mm. The normal (compressive) load imposed is 205 N. The sample shear when the shear force is 125 N.a) Determine the test normal stress and shear stress at failure.b) Determine the angle of internal friction Φ for this soilc) What is probable condition of the tested sample (dense, loose, etc)?
Problem # 5. The angle of friction of compacted dry sand is 37°. In a direct shear test on the sand, normal stress of 150 kN/m^2 was applied. The size of the specimen was 50mm x 50mm 30 mm (height): a. Compute the shearing stress.b. What shear force will cause will cause shear failure?c. Determine the shear stress at a depth 3m. If the void ratio of the soil is 0.60. Sp. Gr. of sand is 2.70.
he following results were obtained from a direct shear test conducted on pure sand: Sample height and diameter = 30 mm and 75 mm respectively. Normal stress = 100 kN/m2 Shear force at failure = 185 N a) Determine the angle of friction for the soil. Round off to one decimal i.e. 99.5! b) What would be the shear force (in N) at failure if the normal stress is 175 kN/m2? Round off to the nearest figure i.e. 300.55 to 301! c) What would be the principal stress at failure? Consider a and b
(a) A sample of dry sand is tested in direct shear. Under an applied normal stress of 4,800 psf, the sample falls when the shear stress reaches 3,100 psf. What is the angle of internal friction for this soil?(b) A second sample of the same sand material is also to be tested in direct shear, but the applied compressive loading will be 3,500 psf instead of 4,800 psf. What shear stress is expected to fail the sample?
An undisturbed soil sample, 110 mm in diameter and 220 mm in height, was tested in a triaxial machine. The sample sheared under an additional axial load of 3.35 kN with a vertical deformation of 21 mm. The failure plane was inclined at 50˚ to the horizontal and the cell pressure was 300 kN/m2. i. Draw the Mohr circle diagram representing the above stress conditions, and from it determine: − Coulomb’s equation for the shear strength of the soil, in terms of total stress; − the magnitude and obliquity of the resultant stress on the failure plane
A triaxial test conducted on cohesionless soil gives the following results: Deviator stress at failure = 410kPa The angle of shearing resistance = 32 degrees Determine the following: a. Confining pressure in kPa b. Shear stress at failure plane in kPa c. Angle that the failure plane makes with the principal plane (degrees)
A dry sand sample in a triaxial test failed when the confining stress (minor principal stress) was 1,000 psf and the axial stress (major principal stress) was 4,000 psf. What is the angle of internal friction for this soil?
The size of a sand specimen in a direct shear test was 50 mm x 50 mm x 30 mm (height). It is known that, for the sand, tan phi prime = 0.65/e (where e = void ratio) and the specific gravity of soil solids Gs = 2.65. During the test, a normal stress of 140 kN/m^2 was applied. Failure occured at a shear stress of 105 kN/m^2. What was the mass of the sand specimen?