A sequence is given by the recurrence relation Xn+1 = Xn + 3(n + 1) for n > 1, and the initial value x1 = 1. (a) Showing your working, use the recurrence relation to compute xn for n = 1, 2, 3 and 4. 3n? + 3n – 4 - (b) Prove for all n >1 that xn 2

Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
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Chapter4: Eigenvalues And Eigenvectors
Section4.6: Applications And The Perron-frobenius Theorem
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A sequence is given by the recurrence relation
Xn+1 = Xn + 3(n + 1) for n > 1,
and the initial value x1 =
= 1.
(a) Showing your working, use the recurrence relation
to compute n for n = 1, 2, 3 and 4.
3n2 + 3n – 4
(b) Prove for all n >1 that xn =
2
Transcribed Image Text:A sequence is given by the recurrence relation Xn+1 = Xn + 3(n + 1) for n > 1, and the initial value x1 = = 1. (a) Showing your working, use the recurrence relation to compute n for n = 1, 2, 3 and 4. 3n2 + 3n – 4 (b) Prove for all n >1 that xn = 2
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