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A series RL circuit with R = 50 2 and L = 10 H has a constant voltage V = 100 V applied at t = 0 by the closing of a switch. the expressions for VR and VL. A VL=100(1-e-5t) and Vr=100e-5t B Vr=-100(1+e-5t) and VL=100e-5t C) Vr=100(1-e-5t) and VL=100e-5t D Vr=-100(1-e-5t) and VL=-100e-5t none of the choices

A series RL circuit with R = 50 2 and L = 10 H has a constant voltage V = 100 V applied at t = 0 by the closing of a switch. the expressions for VR and VL. A VL=100(1-e-5t) and Vr=100e-5t B Vr=-100(1+e-5t) and VL=100e-5t C) Vr=100(1-e-5t) and VL=100e-5t D Vr=-100(1-e-5t) and VL=-100e-5t none of the choices

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter4: Polynomial And Rational Functions
Section: Chapter Questions
Problem 5T
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A series RL circuit with R = 50 2 and L = 10 H has a constant voltage V = 100 V applied at t = 0 by the closing of a switch. the expressions for VR and VL. A VL=100(1-e-5t) and Vr=100e-5t B Vr=-100(1+e-5t) and VL=100e-5t C) Vr=100(1-e-5t) and VL=100e-5t D Vr=-100(1-e-5t) and VL=-100e-5t none of the choices
Transcribed Image Text:A series RL circuit with R = 50 2 and L = 10 H has a constant voltage V = 100 V applied at t = 0 by the closing of a switch. the expressions for VR and VL. A VL=100(1-e-5t) and Vr=100e-5t B Vr=-100(1+e-5t) and VL=100e-5t C) Vr=100(1-e-5t) and VL=100e-5t D Vr=-100(1-e-5t) and VL=-100e-5t none of the choices
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