A small ball of mass 740.0 g is placed in a tube that is bent into a circular arc of radius R= 67.5 cm.The friction between the ball and the walls of the tube is negligible. The ball has an iron core. A magnet is used to raise the ball until it makes an angle of 5.00 degrees with the vertical, and then released from rest. Where will the ball be 1.20 seconds after being released? Express your answer in terms of the angle,θ, that the ball makes with the vertical.

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A small ball of mass 740.0 g is placed in a tube that is bent into a circular arc of radius R= 67.5 cm.The friction between the ball and the walls of the tube is negligible. The ball has an iron core. A magnet is used to raise the ball until it makes an angle of 5.00 degrees with the vertical, and then released from rest. Where will the ball be 1.20 seconds after being released? Express your answer in terms of the angle,θ, that the ball makes with the vertical.

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Step 1

When the ball is at some angle with vertical the restoring force acting is in tangential direction and  is given by,

 

fred=-mgsin(Θ)for small angle sin(Θ)=Θso,fres=-mgΘ     (1)

A cartoon representation of situation is below,

Advanced Physics homework question answer, step 1, image 1

As the particle is moving on circle, r and Θ are the suitable variables to define its position, choosing Θ=0 to be the equilibrium position, the equation of motion of the particle is,

md2 dt2rΘ=fresmrΘ¨=-mgΘrΘ¨+gΘ=0Θ¨+grΘ=0     (2)

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