- A small block of mass 490 g rests close to the left wall of a box of equal mass. Length of the box is 40 cm. The box is placed on a horizontal floor Jubricated with oil. Force of viscous friction of the lubricating oil is given by equation F = -kü, where k = 0.5 kg/s andü is velocity of the box relative to the floor. There is no friction between the block and the floor of the box. If the block is given a velocity 10 m/s towards the right, how many times will the block collide with walls of the box and how far will the box move? Ana! 49¢9.8 thon the

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- A small block of mass 490 g rests close to the left wall of a box of equal
mass. Length of the box is 40 cm. The box is placed on a horizontal floor
lubricated with oil. Force of viscous friction of the lubricating oil is given
by equation F= -kü, where k
relative to the floor. There is no friction between the block and the floor
of the box. If the block is given a velocity 10 m/s towards the right, how
many times will the block collide with walls of the box and how far will
the box move?
0.5 kg/s and ü is velocity of the box
Ana! 49 49.
whon the
Transcribed Image Text:- A small block of mass 490 g rests close to the left wall of a box of equal mass. Length of the box is 40 cm. The box is placed on a horizontal floor lubricated with oil. Force of viscous friction of the lubricating oil is given by equation F= -kü, where k relative to the floor. There is no friction between the block and the floor of the box. If the block is given a velocity 10 m/s towards the right, how many times will the block collide with walls of the box and how far will the box move? 0.5 kg/s and ü is velocity of the box Ana! 49 49. whon the
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