A small block slides down a frictionless track whose shape is described by y = (x^2) /d for x<0 and by y = -(x^2)/d for x>0. The value of d = 4.93m, and x and y are measured in meters as usual. You start the block on the track at rest, somewhere to the left of x = 0. You then release the block from rest and let it slide down. What is the maximum value of x (that is, what is the closest to the origin) from which you can release the block from rest and have it leave the track at x = 0 and go into freefall? -1.75 m -3.38 m -3.59 m -2.47 m
A small block slides down a frictionless track whose shape is described by y = (x^2) /d for x<0 and by y = -(x^2)/d for x>0. The value of d = 4.93m, and x and y are measured in meters as usual. You start the block on the track at rest, somewhere to the left of x = 0. You then release the block from rest and let it slide down. What is the maximum value of x (that is, what is the closest to the origin) from which you can release the block from rest and have it leave the track at x = 0 and go into freefall? -1.75 m -3.38 m -3.59 m -2.47 m
Related questions
Question
A small block slides down a frictionless track whose shape is described by y = (x^2) /d for x<0 and by y = -(x^2)/d for x>0. The value of d = 4.93m, and x and y are measured in meters as usual.
You start the block on the track at rest, somewhere to the left of x = 0. You then release the block from rest and let it slide down. What is the maximum value of x (that is, what is the closest to the origin) from which you can release the block from rest and have it leave the track at x = 0 and go into freefall?
-1.75 m
|
||
-3.38 m
|
||
-3.59 m
|
||
-2.47 m
|
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 2 steps with 2 images