A small generator burns two types of fuel low sulfur and high sulfur to produce electricity. For one hour, each gallon of low sulfur emits 3 units of sulfur dioxide, generates 4 kilowatts of electricity and costs P200. Each gallon of high sulfur emits 5 units of sulfur dioxide, generates 4 kilowatts and costs P220. The Environmental Protection Agency insists that the maximum amount of sulfur dioxide that can be emitted per hour is 15 units. Suppose at least 16 kilowatts must be generated per hour, what is the appropriate objective function if the company would like to have the most economical mix? Let x be the number of units of low sulfur fuel and y be the number of high sulfur fuel. (A) Max P = 220x+ 200y (B) Min C=200x + 220y Max P=200x + 220y (D) Min C 220x+ 200y
A small generator burns two types of fuel low sulfur and high sulfur to produce electricity. For one hour, each gallon of low sulfur emits 3 units of sulfur dioxide, generates 4 kilowatts of electricity and costs P200. Each gallon of high sulfur emits 5 units of sulfur dioxide, generates 4 kilowatts and costs P220. The Environmental Protection Agency insists that the maximum amount of sulfur dioxide that can be emitted per hour is 15 units. Suppose at least 16 kilowatts must be generated per hour, what is the appropriate objective function if the company would like to have the most economical mix? Let x be the number of units of low sulfur fuel and y be the number of high sulfur fuel. (A) Max P = 220x+ 200y (B) Min C=200x + 220y Max P=200x + 220y (D) Min C 220x+ 200y
Algebra for College Students
10th Edition
ISBN:9781285195780
Author:Jerome E. Kaufmann, Karen L. Schwitters
Publisher:Jerome E. Kaufmann, Karen L. Schwitters
Chapter12: Algebra Of Matrices
Section12.CR: Review Problem Set
Problem 37CR
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