A solid disc with radius R is connected to spring at point (d) distance abovethe center of disc. The other end of the spring is fixed to the vertical wall. Thedisc is free to roll without slipping on the ground. The mass of disc is (M) andthe spring constant is (K). The polar moment of inertia for disc about itscenter is J = 1/2MR2 , so the natural frequancy for the system is12K(R+d)²MR2the Answer is O12K2п3M

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A solid disc with radius R is connected to spring at point (d) distance above the center of disc. The other end of the spring is fixed to the vertical wall. The disc is free to roll without slipping on the ground. The mass of dise is (M) and the spring constant is (K). The polar moment of inertia for disc about its center is J 1/2MR2 , so the natural frequancy for the system is

A solid disc with radius R is connected to spring at point (d) distance above the center of disc. The other end of the spring is fixed to the vertical wall. The disc is free to roll without slipping on the ground. The mass of dise is (M) and the spring constant is (K). The polar moment of inertia for disc about its center is J 1/2MR2 , so the natural frequancy for the system is

International Edition---engineering Mechanics: Statics, 4th Edition

4th Edition

ISBN:9781305501607

Author:Andrew Pytel And Jaan Kiusalaas

Publisher:Andrew Pytel And Jaan Kiusalaas

Chapter9: Moments And Products Of Inertia Of Areas

Section: Chapter Questions

Problem 9.40P

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