A steel ball is launched from an initial height of 5,376 feet. The height of the steel ball at time t seconds is given by h(t) = –16t² + 256t + 5376. Find the time t guaranteed by the Mean Value Theorem when the instantaneous velocity of the steel ball is equal to the average velocity during its trajectory. Assume the interval under consideration is [0, t* ] where t* is the time that the ball hits the ground. (Do not include "t =" or "seconds" in your answer.)

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section5.6: Exponential And Logarithmic Equations
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Use the Mean Value Theorem in velocity problems
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A steel ball is launched from an initial height of 5,376 feet. The height of the steel ball at timet seconds is given by
h(t) = –16t2 + 256t + 5376. Find the time t guaranteed by the Mean Value Theorem when the instantaneous velocity of
the steel ball is equal to the average velocity during its trajectory. Assume the interval under consideration is [0, t*] where
t* is the time that the ball hits the ground.
(Do not include "t =" or "seconds" in your answer.)
Provide your answer below:
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Transcribed Image Text:13:56 4月4日周日 * 92% A knewton.com CURRENT OBJECTIVE Use the Mean Value Theorem in velocity problems Question A steel ball is launched from an initial height of 5,376 feet. The height of the steel ball at timet seconds is given by h(t) = –16t2 + 256t + 5376. Find the time t guaranteed by the Mean Value Theorem when the instantaneous velocity of the steel ball is equal to the average velocity during its trajectory. Assume the interval under consideration is [0, t*] where t* is the time that the ball hits the ground. (Do not include "t =" or "seconds" in your answer.) Provide your answer below: FEEDBACK MORE INSTRUCTION SUBMIT Content attribution Way to go! You completed 1 of 5 objectives!
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