A stone is launched vertically upward from a cliff 48 ft above the ground at a speed of 32 ft/s. Its height above the ground t seconds after the launch is given by s = - 16t +32t + 48 for 0sts3. When does the stone reach its maximum height? Find the derivative of s. s' = D The stone reaches its maximum height at (Simplify your answer.) S.

Functions and Change: A Modeling Approach to College Algebra (MindTap Course List)
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ISBN:9781337111348
Author:Bruce Crauder, Benny Evans, Alan Noell
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Chapter2: Graphical And Tabular Analysis
Section2.1: Tables And Trends
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A stone is launched vertically upward from a cliff 48 ft above the ground at a speed of 32 ft/s. Its height above the ground t seconds after the
launch is given by s = - 16t +32t + 48 for 0sts3. When does the stone reach its maximum height?
Find the derivative of s.
s' =
D
The stone reaches its maximum height at
(Simplify your answer.)
S.
Transcribed Image Text:A stone is launched vertically upward from a cliff 48 ft above the ground at a speed of 32 ft/s. Its height above the ground t seconds after the launch is given by s = - 16t +32t + 48 for 0sts3. When does the stone reach its maximum height? Find the derivative of s. s' = D The stone reaches its maximum height at (Simplify your answer.) S.
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