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A stone is thrown with an initial velocity of 35 ft/s from the edge of a bridge that is 47 ft above the ground. The height of this stone above the ground t seconds after it is thrown is f(t) = - 16t + 35t + 47. If a second stone is thrown from the ground, then its height above the ground after t seconds is given by g(t) = – 16t + vot, where vo is the initial velocity of the second stone. Determine the value of vo such that the two stones reach the same high point. When an object that is thrown upwards reaches its highest point (just before it starts to fall back to the ground), its will be zero. Therefore, to find the maximum height of the object thrown from the bridge, use the equation, The initial velocity of the second stone would need to be vo (Do not round until the final answer. Then round to one decimal place.)

A stone is thrown with an initial velocity of 35 ft/s from the edge of a bridge that is 47 ft above the ground. The height of this stone above the ground t seconds after it is thrown is f(t) = - 16t + 35t + 47. If a second stone is thrown from the ground, then its height above the ground after t seconds is given by g(t) = – 16t + vot, where vo is the initial velocity of the second stone. Determine the value of vo such that the two stones reach the same high point. When an object that is thrown upwards reaches its highest point (just before it starts to fall back to the ground), its will be zero. Therefore, to find the maximum height of the object thrown from the bridge, use the equation, The initial velocity of the second stone would need to be vo (Do not round until the final answer. Then round to one decimal place.)

College Algebra
College Algebra
7th Edition
ISBN:9781305115545
Author:James Stewart, Lothar Redlin, Saleem Watson
Publisher:James Stewart, Lothar Redlin, Saleem Watson
Chapter3: Polynomial And Rational Functions
Section3.1: Quadratic Functions And Models
Problem 56E: When a certain drug is taken orally, the concentration of the drug in the patient's bloodstream...
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A stone is thrown with an initial velocity of 35 ft/s from the edge of a bridge that is 47 ft above the ground. The height of this stone above the ground t seconds after it is thrown is f(t) = - 16t + 35t + 47. If a second stone is thrown from the ground, then its height above the ground after t seconds is given by g(t) = - 16t + vot, where v, is the initial velocity of the second stone. Determine the value of vo such that the two stones reach the same high point. When an object that is thrown upwards reaches its highest point (just before it starts to fall back to the ground), its will be zero. Therefore, to find the maximum height of the object thrown from the bridge, use the equation, The initial velocity of the second stone would need to be vo (Do not round until the final answer. Then round to one decimal place.)
Transcribed Image Text:A stone is thrown with an initial velocity of 35 ft/s from the edge of a bridge that is 47 ft above the ground. The height of this stone above the ground t seconds after it is thrown is f(t) = - 16t + 35t + 47. If a second stone is thrown from the ground, then its height above the ground after t seconds is given by g(t) = - 16t + vot, where v, is the initial velocity of the second stone. Determine the value of vo such that the two stones reach the same high point. When an object that is thrown upwards reaches its highest point (just before it starts to fall back to the ground), its will be zero. Therefore, to find the maximum height of the object thrown from the bridge, use the equation, The initial velocity of the second stone would need to be vo (Do not round until the final answer. Then round to one decimal place.)
Let C(x) represent the cost of producing x items and p(x) be the sale price per item if x items are sold. The profit P(x) of selling x items is P(x) dP P(x) = xp(x) - C(x) (revenue minus costs). The average profit per item when x items are sold is and the marginal profit is X . The dx marginal profit approximates the profit obtained by selling one more item given that x items have already been sold. Consider the following cost functions C and price functions p. Complete parts a through d below. C(x) = - 0.01x + 130x + 100, p(x) = 300 – 0.1x, a = 600 a. Find the profit function P. The profit function is P(x) =
Transcribed Image Text:Let C(x) represent the cost of producing x items and p(x) be the sale price per item if x items are sold. The profit P(x) of selling x items is P(x) dP P(x) = xp(x) - C(x) (revenue minus costs). The average profit per item when x items are sold is and the marginal profit is X . The dx marginal profit approximates the profit obtained by selling one more item given that x items have already been sold. Consider the following cost functions C and price functions p. Complete parts a through d below. C(x) = - 0.01x + 130x + 100, p(x) = 300 – 0.1x, a = 600 a. Find the profit function P. The profit function is P(x) =
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