A symmetrical parabolic curve connects two grades of 6% and -4%. It is to passthrough a point “P”on the curve at station 25 + 140 having an elevation of 98.34. If theelevation of the grade of intersection is 100m with a stationing of 25 + 160. Calculate the following: It the curve a sag or a summit? Length the curve Stationing of the highest/lowest point on the curve. Eleavtion of station 25 + 120 on the curve.

Q: The tangents of a sag curve connects at the point of intersection having Station 18+448 and…

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Q: Suppose that during the construction of the symmetrical curve in problem # dscovered that left side…

A: Solution: 2 Considering the diagram

Q: 3. A reverse curve is to be inserted between parallel tangents 50 m apart with AD 350 m, and R2 =…

A: H=350m

Q: A circular curve of 609.6 m radius joins two points A and C which lie on the two straights AB and…

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Q: The tangents of a sag curve connects at the point of intersection having Station 18+427.14 and…

A: We have to determine the determine the value of the maximum offset in meters as per the given data…

Q: It is required to construct a vertical curve with 400m from the PC at  STA 3+16, elev.214m to the…

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Q: 3. Given a simple horizontal curve with A-8 00 00" and Pl at station 104450, calculate: a. R b. T d.…

A: a) Radius R = 1720 / D                    = 1720 /8                  = 215 m b) T = Radius x  tan…

Q: A +3.9% back tangent intersect at -2.8% forward tangent at PI, whose station is 6+200 and elevation…

A: Station of PI = 6+200 = 6200 Elevation of PI = 150m

Q: Q6/A grade gl of+ 1.23% intersects grade g2 of -2.75% at a vertex whose station 18+00 and elevation…

A: Given:- The gradient of first tangent = g1 = +1.23% The gradient of second tangent = g2 = -2.75%…

Q: Problems: 1. A 6.2% grade is followed by -2.8% grade; the grades intersecting at sta. + 800 of…

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Q: SITUATION 8: A parabolic sag curve has tangent grades of -2% and +3%. The stationing of PT is at…

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Q: The back tangent of a vertical curve has a grade of 2% and a forward tangent of -3.3%. Compute the…

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Q: The tangents of a sag curve connects at the point of intersection having Station 18+444.82 and…

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Q: A parabolic vertical curve is to be set out connecting two uniform grades of +1.8 and +3.9%. The…

A: Length=Ar=3.9-1.80.0520m=840mPVCsta=PVIsta-L2PVCsta=2705-8402=2285PVCELV=PVIELV-g1L2PVCelv=238.755-0…

Q: 2. An unsymmetrical parabolic curve has a forward tangent of +8% and a back tangent of -5%. The…

A: Note-Since we answer one question at a time so we will answer the first one. Please resubmit another…

Q: SURVEYING 103 C2 Problem set: as An unsymmetrical parabolic curve has a forward tangent of-8% and…

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Q: A grade line having a slope of 5% intersect another grade line BC having a slope of -3% at vertex…

A: Given Data: g1=5%g2=-3%PC=95mPT=97 mLength of curve=200 mIt is asked to find elevation at quarter…

Q: 2. A grad of 1.5% intersects a grade of -2.5% at station 1+080 of elevation 68.94m. If the summit is…

A: Solution-The given values are as follows  The grade g1=1.5%The grade g2=-2.5%Station…

Q: A vertical parabolic curve is to connect a back tangent of -2% and a forward tangent of +3%. The…

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Q: SITUATION VI. A vertical symmetrical sag curve has a descending grade -5.2% and an ascending grade…

A: The symmetrical vertical curve can be solved by direct formulae as below -

Q: If the stationing Pl of spiral curve is at 13 + 184.43 and if R of a simple curve is 273.49m, angle…

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Q: A 1200 feet parabolic vertical curve has an entering grade of –2.6% and a departing grade of +3.4%.…

A: PVC Station…

Q: b. Location of the summit from PT.

A: GivenPVI=35+300PVIelv=210so,PVCsta=35300-L2PVCelv=210-(0.061)L2Equation of the…

Q: SURVEYING 103 Problem set: An unsymmetrical parabolic curve has a forward tangent of -8% and back…

A: The practise, profession, art, and science of identifying the terrestrial or three-dimensional…

Q: CONNECT A FORWARD TANGENT OF 3% AND A BACK TANGENT OF-15% BY A 300 M SYMMETRICAL PARABOLIC CURVE. IT…

A: Given: The grade g1 is -15%. The grade g2 is 3%. The length of the curve is 300 m. The station at PI…

Q: a vertical summit curve is having tangents which intersects at point Pl at station 12+615.61 and…

A: This question belongs to subject surveying. In this question we find out the elevation of point…

Q: A symmetrical vertical summit curve has tangents of +4% and -2%. The allowable rate of change of…

A: Question is based on the summit curve . Gradients of curve, allowable rate of change of grades and…

Q: A vertical summit curve has a backward tangent of+5% and a forward tangent of -8%,what is the…

A: Given:- The grade of the backward tangent = +5% The grade of the forward tangent = -8% The length of…

Q: Q 3: A horizontal curve of a 4-lane undivided highway is built in acut section of side slope 3:1. If…

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Q: b. 500 m c. 360 m d. 527 m 2. Find the stationing of PC.  a. 7+589

A: Length=Ar=0.03+0.020.00220m L=500m

Q: It is required to construct a vertical curve with 400m from the PC atS TA 3+16, elev.214m to the…

A: A station is a precise location on the Earth that has been identified by surveying procedures.…

Q: Part of a 120 m long vertical curve road connecting a rear tangent mile (+1.85%) and a base tangent…

A: Length of Curve = 120 m Rear tangent Mile = 1.85% Base Tangent Mile = -3.65% Intersection Station…

Q: SIMPLE AND COMPOUND CURVES 1. Two tangents intersecting at V with bearings of N 75 12'E and S 78 36…

A: Given - Bearing = N75∘12'E  and S78°36'ED1 = 4°New lenght of the curve = L2 = 100m   Initial…

Q: nd N60°E respectively. If the project Engineer runs the compound curve starting at the point of…

A: Given:- forward tangent bearing=S65E Backward tangent bearing=N60E point of curvature at…

Q: It is required to construct a vertical curve with 400m from the PC at STA 3+16, elev.214m to the…

A:

Q: A simple curve connects two tangents AB and BC with bearings N85°30’E and S68°30’E, respectively.…

A: Given:- The bearing of tangent AB = N85°30’E  The bearing of tangent BC = S68°30’E The coordinates…

Q: A simple curve connects two tangents AB and BC with bearings N85030’E and S68030’E, respectively.…

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Q: The length of curve at side of PC is 45 while on the PT is 5 having an elevation of 108.6 is found…

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Q: A symmetrical parabolic curve passes through point A whose elevation is 23.33m at a distance of 54m…

A: The given data is shown below: Elevation from PC=23.33 mDistance from PC=54 mElevation of PC at…

Q: Q2/ A grade gl of + 1.23% intersects grade g2 of - 2.75% at a vertex whose station 18+00 and…

A: A curve that provides a transition between two tangents of a roadway that allow a vehicle to…

Q: Two A -6% grade and a 2% grade intersect at station 12+200 whose elevation is 45.673m. The two…

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Q: Two tangents of a simple curve have  an azimuth of 250⁰15’ and 280⁰15’  respectively and intersect…

A: Given Initial azimuths = 250⁰15’ and 280⁰15’

Q: 3. A symmetrical parabolic curve is designed to pass through a point A whose elevation is 22.995m at…

A: In the above discussed problem the curve is parabolic curve, the general equation for this curve is…

Q: In a railroad simple curve, the angle of intersection of tangents is 63⁰04’ and its distance is…

A: Length of curve of the given simple circular curve is found to be=88.14m For explanation please see…

Q: Problem No. 1 A symmetrical parabolic curve connects two grades of 6% and -4%. It is to pass through…

A: The given data is as follows: Grades in curve=6%                             =-4%Stationing of point…

Q: An ascending grade of 3.7% intersects another grade at STA 12+598 whose elevation is 597m. The…

A: Given- G1=3.7%Station of PVI=12+598Elevation of PVI=597mL=800m

Q: An ascending grade of 4.9% intersects another grade at STA 12+598 whose elevation is 500m. The…

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Q: cost of excavation, the symmetrical curve is to be adjusted by adding a fill 0.4174m I the curve at…

A: Hi! Thank you for the question As per the honor code, We’ll answer the first question since the…

Q: A 3% ascending grade meets a descending grade at the vertex at station 2+050 and elevation 100m with…

A: Stationing of highest point is also, written as Sta HP It is expressed as ; Station of highest point…

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