A symmetrical parabolic curve passes through point A whose elevation is 23.23 m at a distance of 54 m from the PVC. The elevation of the PVC at Station 4 + 100 is 22.56 m. The grade of the back tangent is +2% and the length of the curve is 120 m. 1. Compute the grade of the forward tangent. 2. Compute the stationing of the highest point of the curve. 3. Compute the elevation of the highest point of the curve.
A symmetrical parabolic curve passes through point A whose elevation is 23.23 m at a distance of 54 m from the PVC. The elevation of the PVC at Station 4 + 100 is 22.56 m. The grade of the back tangent is +2% and the length of the curve is 120 m. 1. Compute the grade of the forward tangent. 2. Compute the stationing of the highest point of the curve. 3. Compute the elevation of the highest point of the curve.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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A symmetrical parabolic curve passes through point A whose
elevation is 23.23 m at a distance of 54 m from the PVC. The
elevation of the PVC at Station 4 + 100 is 22.56 m. The grade of
the back tangent is +2% and the length of the curve is 120 m
Transcribed Image Text:Vertical Curve
A symmetrical parabolic curve passes through point A whose
elevation is 23.23 m at a distance of 54 m from the PVC. The
elevation of the PVC at Station 4 + 100 is 22.56 m. The grade of
the back tangent is +2% and the length of the curve is 120 m.
1. Compute the grade of the forward tangent.
2. Compute the stationing of the highest point of the curve.
3. Compute the elevation of the highest point of the curve.
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