A tank holds 138 gallons of water. Initially, at t=0, a solution containing 1/8 lb/gal of a chemical solvent flows into the tank at a rate of 6 gal/min. The mixture then leaves the tank at the same rate. The amount of chemical (water with solvent) at any instant t, inside the tank, corresponds to 3 (1+e-6t/138) O a) 92 3 O b) :(1 – e 6t/138) 92 69 Oc) (1. Be/138 ) - e 69 (1+e-6t/138) 4 d)

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