Asap plz handwritten solution acceptable A tank originally contains 100 gallons of fresh water. Then water containing 0.25 lbs of salt per gallon is poured into the tank at a rate of 8 gallons per minute, and the mixture is allowed to leave at the samerate.(a) Let A (t) denote the amount of salt in the tank at time t (in minutes). Determine the solution and how much salt there is in the tank in 10 minutes:2t(215)(0 ≤ t ≤ 10 )A (t):=A (10)=-(25 - 25e25 - 25e30.67e-(1)(b) After 10 minutes the process is stopped, and fresh water is poured into the tank at a rate of 8 gallons per minute with the mixture again leaving at the same rate. Determine the solution A (t) for t > 10 andhow much salt there is in the tank in an additional 10 minutes (20 minutes overall):A (t) =2t(2/3)25-(Xlbs( t > 10 )lbsA (20) = 30.85XNote: Use the A (10) as the initial condition rather than A (0)!

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A tank originally contains 100 gallons of fresh water. Then water containing 0.25 lbs of salt per gallon is poured into the tank at a rate of 8 gallons per minute, and the mixture is allowed to leave at the same rate. (a) Let A (t) denote the amount of salt in the tank at time t (in minutes). Determine the solution and how much salt there is in the tank in 10 minutes: - (1/1) A (t) = 25-25e A (10) = -(1) 25 - 25e A (t)= 30.67e (b) After 10 minutes the process is stopped, and fresh water is poured into the tank at a rate of 8 gallons per minute with the mixture again leaving at the same rate. Determine the solution A (t) for t > 10 and how much salt there is in the tank in an additional 10 minutes (20 minutes overall): - ( 11 ) X (0 ≤ t ≤ 10 ) lbs ( t > 10 ) lbs A (20) = 30.85 X Note: Use the A (10) as the initial condition rather than A (0)!