(a) The curve y = 1/(1 + x-) is called a witch of Maria Agnesi. Find an equation of the tangent line to this curve at the point (1, X-

Q: Find the equation of the tangent line to the curve y = √-4 at the point (5,1). Oy=-1 Oy=-1 Oy=2x-2

A: Given y=x-4       point (5,1)To find equation of tangent line:

Q: Find the equation of the tangent line at the given value of x on the curve. y° +xy² -61=x+3y°; x:…

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Q: Find an equation of the tangent line to the curve at the given point. 6. y =x² – 3x +1, (2, –1)

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Q: Find an equation of the tangent line to the curve at the given point. 2x + 1 y x + 2 (1, 1)

A: Given, y=2x+1x+2Point=1, 1

Q: Find the equation of the tangent line to the curve y = (2 + x)e¬* at the point (0,2)

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Q: Find an equation of the tangent line to the graph of the equation  x + y − ex − y = 3 at the point…

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Q: Find an equation of the tangent line to the curve at the given point. 2 y = x + -, x (2,3)

A: Given,          The curve is y=x+2x and the point is 2,3.

Q: Find an equation of the tangent line to the curve at the given point. y =  4x x + 3 ,…

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Q: Find the equation of the tangent line to the curve y- (1+2x) at the point (1,9)

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Q: Find the equation of the tangent line to the graph of y(x) = 12( - ;)' at æ = 2. Equation of the…

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Q: Find an equation of the tangent line to the given curve at the specified point. x2 - 1 y : x2 + x +…

A: The equation of the given curve: y=x2-1x2+x+1

Q: 3) Find the equation of the tangent line to the curve the point (1, 1). y²(2 – x) = x³ at

A: Given curve is : y2(2-x) = x3

Q: Find an equation of the tangent line to the curve at thegiven point  y = ln ( x 2- 3x + 1 )       ,…

A: Given,y = ln (x2-3x+1)slope of tangent line is equal to the first derivative of curve at given point

Q: Find the equation of the tangent line to the curve of y = 1/x at the point (3, 1/3)

A: Slope of the tangent line is the derivative of the given curve at the given point. So…

Q: Find an equation of the tangent line to the curve at the given point    y= xe^-x^2 , (0,0)

A: Given,

Q: Find an equation of the tangent line to the graph of y = e at the point 2, y =

A: The given function is:y=e-x2The point is 2, 1e4

Q: What is the equation of the tangent line to the curve y= In(x“ + 1) at x=1?

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Q: Find an equation of the tangent line to the graph of the equation x2+9xy +y2 =25 at point (0, 5)

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Q: Find an equation of the tangent line to the curve at the following point:  y=4/1+e^-x, (0,2) y=?

A: We first find the slope of the tangent using the first derivative y=41+e-xy=4(1+e-x)-1…

Q: 1. Find the equation of the tangent line and normal line to the graph of y=√x² +3 at the point (-12)

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Q: An equation of the tangent line to the curve y = sin(x) at x = Зп /4 is %3D y = - (х — Зп /4) .

A: As per our guidelines we are suppose to solve only first question. Kindly repost the other question…

Q: Find an equation of the tangent line to the curve y Inx" – x² at the point where x = 1.

A: The given curve is y=lnxx-x2 at the point where x=1. Find the equation of tangent.

Q: The equation of the tangent line to the curve y = x2 – 4x at the point where the curve crosses the…

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Q: 2) Find the equation of the tangent line to the curve y = cos(2x+ at x =

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Q: Find an equation of the tangent line to the curve at the given point. 2x (0, 0) (x + 1)2'

A: The given curve y=2xx+12, at the point 0,0

Q: Find an equation of the tangent line to the curve y=9^(tan(9x)) at the point (0,1)

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Q: Find the equation of the tangent line to the curve y=x4 at the point (−1,1).

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Q: find an equation of the tamgent line to the given curve at the specified point

A: We find the derivative of the given function first. using quotient rule

Q: Find an equation of the tangent line to the curve at the given point. y = (1 + 3x)1, (0, 1)

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Q: An equation of the tangent line to the curve C at the point (1, 2) is

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Q: Find an equation for the tangent line to y =-3x- at the point x =-1.

A: We have to find equation of tangent line to the curve y=-3x2-1x3 at the point x=-1 To find the…

Q: Find the equation of the tangent line to the curve y = e - x that is parallel to the line y = 1 - 2…

A: Consider the curves, y=e-x…

Q: Find an equation for the tangent to the curve y = at x=2

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Q: 9. Find the equation of the curve whose y" e*. = - cos x + 6x + 4 with horizontal tangent at the…

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Q: Find an equation of the tangent line to the curve at the given point. y = sin(21n x), (1,0)

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Q: 2. Find the equation of the tangent line to y at x = -5.

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Q: Find the equation of the tangent line to the graph of x^2y-xy^4=-1830 at (3,5)

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Q: Find an equation of the tangent line to the curve at the given point. y = 4*, (0, 1)

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Q: Find the equation of the tangent line at the given point on the curve. x3 + 2xy – y2 = 11 at (2,3)

A: We need to find the equation of the tangent line at the given point on the curve. We have x3+2xy-y2…

Q: Find the equation of the tangent line to the curve y=x-6cos(x) at the point (0,-6)

A: We have to find equation of tangent line to the curve y=x-6cos(x) at the point (0,-6)  Now first we…

Q: Find the equation of the tangent line at the point (1,0) to the curve implicitly defined by In(x +…

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Q: Find an equation of the tangent line to the curve at the given point:  y=(2x+1)/(x+2) ,    (1,1)

A: To determine the equation of the tangent line.

Q: The slope of the tangent line to the curve y=2e10xcos(-6x) at x-0 is

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Q: 3 - at the point (3, 1) is: The slope of the tangent line to the curve y The equation of this…

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Q: The slope of the tangent line to the graph of xy = In(x² + y²) at the point (1, 0) is

A: You have asked multiple unrelated questions in the same post. I have addressed the first one. Please…

Q: Find an equation of the tangent line to the curve at the given point. y = cos (x² – 2x + 1), (1, 1).

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Q: Find the equation of the tangent line to the curve at the point (5,3) given that x2+xy+2y2=58

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Q: Find an equation of the tangent line to the curve at the given point. y = In(x² - 3xt 1), (3, 0) y…

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Q: The equation of the tangent line to the curve y=x² +1 at x = -4

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Q: Find the x-coordinate of the point on the graph of y=x^2 where the tangent line is parallel to the…

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