Please provide the (x,y) with the answer of the graph of both questions. O GRAPHS ANDTransforming the graph of a function by reflecting over an axisEspañol(a) The graph of y=f(x) is shown. Draw the graph of y=-f(x).(b) The graph of y=g(x) is shown. Draw the graph of y=g(-x).4-2--2-AaExplanationCheckAccessibilitO 2021 McGraw Hill LLC. All Rights Reserved. Terms of Use I Privacy Centertv5,030NOV4.MacBook Air8 图8图

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Answered: (a) The graph of y=f(x) is shown. Draw…

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018

18th Edition

ISBN:9780079039897

Author:Carter

Publisher:Carter

Chapter1: Expressions And Functions

Section1.8: Interpreting Graphs Of Functions

Problem 18PPS

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The graph of a function f is given. The x y-coordinate plane is given. A curve with 2 parts is graphed. The first part is linear, enters the window in the second quadrant, goes down and right, crosses the x-axis at x = −1, and ends at the open point (0, −1). The second part is linear, begins at the closed point (0, 2), goes down and right, crosses the x-axis at x = 2, and exits the window in the fourth quadrant. Determine whether f is continuous on its domain. continuous not continuous     If it is not continuous on its domain, say why. lim x→0 f(x) ≠ f(0) lim x→0+ f(x) ≠ lim x→0− f(x), so lim x→0 f(x) does not exist.      The graph has discontinuities at the end points. The graph is continuous on its domain.
The graph of a function f is given. The x y-coordinate plane is given. A curve with 3 parts is graphed. The first part is linear, enters the window in the second quadrant, goes down and right, crosses the x-axis at approximately x = −0.33, crosses the y-axis at y = −0.25, and ends at the open point (1, −1). The second part is the point (1, 1). The third part is linear, begins at the open point (1, −1), goes up and right, crosses the x-axis at x = 2, and exits the window in the first quadrant. Determine whether f is continuous on its domain. continuous not continuous     If it is not continuous on its domain, say why. lim x→1+ f(x) ≠ lim x→1− f(x), so lim x→1 f(x) does not exist. The function is not defined at x = 1.     The graph is continuous on its domain. lim x→1 f(x) = −1 ≠ f(1)
Analyze and sketch the graph of the function. Identify any intercepts, relative extrema, points of inflection, and asymptotes y = 4x2 − 8x + 2 x-intercept    (smaller x-value) (x, y) = x-intercept    (larger x-value) (x, y) = y-intercept     (x, y) = relative maximum     (x, y) = relative minimum     (x, y) = point of inflection     (x, y) = horizontal asymptote     vertical asymptote
6) Find the local maximum and minimum values and saddle point(s) of the function. If you have three-dimensional graphing software, graph the function with a domain and viewpoint that reveal all the important aspects of the function.
A right triangle has one vertex on the graph of y=x3,x >0 at another at the origin,and the third on the positive y-axis at as shown in the figure.Express the area A of the triangle as a function of x.
The x y-coordinate plane is given. A point, a vertical dashed line, and a function are on the graph. The point occurs at the point (3, 2). The vertical dashed line crosses the x-axis at x = 5. The curve enters the window in the second quadrant goes up and right, sharply turns at the approximate point (−5, 3.5), goes down and right, passes through the open point (−4, 2), crosses the x-axis at x = −3, ends at the closed point (−2, 1), restarts at the open point (−2, 0), goes down and right, exits the window almost vertically just left of the y-axis, reenters the window almost vertically just right of the y-axis, goes down and right, passes through the open point (1, 2), changes direction at the approximate point (2.2, 0.1), goes up and right, ends at the open point (3, 1), restarts at the open point (3, −1), goes down and right, exits the window almost vertically just left of the vertical dashed line at x = 5, reenters the window just right of the vertical dashed line at x = 5, goes up…
Determines the local maximum and minimum values and the saddle point or points of the function. Graph the function with a domain and point of view that reveal all the important aspects of the function
A right triangle is formed in the first quadrant by the x- and y-axes and a line through the point (1, 2). (a) Write the length L of the hypotenuse as a function of x. (b) Use a graphing utility to approximate x graphically such that the length of the hypotenuse is a minimum. (c) Find the vertices of the triangle such that its area is a minimum.
A right triangle has one vertex on the graph of y = x3, x > 0, at (x, y) another at the origin, and the third on the positive y-axis at (0, y). Express the area A of the triangle as a function of x.
Application of derivative Optimization We are going to fence in a rectangular field. Starting at the bottom of the field and moving around the field in a counter clockwise manner the cost of material for each side is $6/ft, $9/ft, $12/ft and $14/ft respectively. If we have $1000 to buy fencing material determine the dimensions of the field that will maximize the enclosed.
Sketch the graph of the given function. Check your sketch using technology. f(x)=x^2+2x+1 (a) indicate the X and Y intercepts. (b) indicate any minimum extrema (c) indicate any points of inflection.
Analyze and sketch the graph of the function. Identify any intercepts, relative extrema, points of inflection, and asymptotes. f(x) = 5x/ x2 +25 x-intercept(x, y) = y-intercept(x, y) = relative maximum (x, y) = relative minimum (x, y) = point of inflection (smallest x-value)(x, y) = point of inflection(x, y) = point of inflection (largest x-value)(x, y) = horizontal asymptote= vertical asymptote=

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(a) The graph of y=f(x) is shown. Draw the graph of y=-f(x). (b) The graph of y=g(x) is shown. Draw the graph of y=g(-x). y 6- -4- -4- 2- -4- 8图