(a) The solutions of the trigonometric equation tan(30) +1 = 0 are: 37 kT ; + ka (i) + kT (ii) 4 (iii) (iv) Not listed + 4 4 3 tan(30) = -1 9 tano SIA where k is an integer. ' (0,) tan o = -1

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A: Please see the answer of the first question below as per the guidelines of Bartleby.

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A: Given query is to find the value of sin2x.

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A: A detailed solution is given below.

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A: we have to find minor and cofactor

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A: Given : 630    630°=360°+270°

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A: Please see the answer below.

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A: We have to find out the value

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Q: b) cos 2B

A: using  cos(2B)=cos2B-sin2B ....(1)

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A: Given,  x4+2x2+17x-48

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A: We can answer the correct answer as below.

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A: Given: 14log3a20+3log3a2We know that   nlogba=logbanThen14log3a20+3log3a2=log3a2014+log3a23We know…

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A: Find your answer below

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Q: 27. 9Co

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A: In the given problem we have to find the component form of given vector . We find component by find…

Q: •sin ² (x/2) = = (tan x sin x)/ 2tan x = sin ² (x/2) •tan x - cot x = - 2cot 2x •sin ² (x/2) = (sin…

A: 3) sin2x2=sinx tanx22=sin2x2 4) sin2x=2cos2(x/2)1-cosx=sin2x 5) 2sinx-sin2x/(2sinx+sin2x)=tan2x/2

Q: For the vector, find V v = (-5, 3) v= -V 4V = || -V, and 4V.

A: Given : 1)V=-5,32)V=2i+6j   To Find : 1) 12v2)  -v3)  4v