A town with a population of 5,000 grows 3%per year. Find the population at the end of 10 years. 9:58ull LTE 2scarsdaleschools.k12.ny.usExponential Word Problems: Growth & DecayGrowth Formula: y = a (1 + r)Decay Formula: y = a (1 – r)where a = original number; r = rate (% in decimal form); t = time periodsWrite an exponential function to model each situation. Find each amount at the endof the specified time. Round your answers to the nearest whole number.1. A town with a10 years.lation of 5,000 grows 3% per year. Find the population at the end of2. Amy makes an initial investment of $5000. The investment loses 13.5% each year.Find the amount Amy has at the end of 8 years.3. Suppose you deposit $1000 in a college fund that pays 7.2% interest compoundedannually. Find the account balance after 5 years.4. Suppose the account in #3 above paid interest quarterly instead of annually. Find theaccount balance after 5 years.5. The population of Boomtown is 475,000 and is increasing at a rate of 3.75% each year.When will the population exceed 1 million people (to the nearest year)?6. The population of Leavetown is 123,000 and is decreasing at a rate of 2.375% eachyear.When will the population of Leavetown drop below 50,000 (to the nearest year)?What will the population of Leavetown be 100 years from now?7. The 1989 population of Mexico was estimated at 87,000,000. The annual growth rate is2.4%. When will the population reach 100,000,000 (to the nearest year)?8. The population of Smalltown in the year 1890 was 6,250. Since then, it has increasedat a rate of 3.75% each year.What was the population of Smalltown in the year 1915?In 1940?What will the population of Smalltown be in the year 2003?When will the population reach 1,000,000 (to the nearest year)?9. A radioactive element decays at a rate of 5% annually. There are 40 grams of thesubstance present.How much of the substance remains after 30 years (to the nearest tenth)?When will the amount of the substance drop to below 20 grams (to the nearestyear)?

Name: A town with a population of 5,000 grows 3%per year. Find the populati
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Description: A town with a population of 5,000 grows 3%per year. Find the population at the end of 10 years. 9:58ull LTE 2scarsdaleschools.k12.ny.usExponential Word Problems: Growth & DecayGrowth Formula: y = a (1 + r)Decay Formula: y = a (1 – r)where a = origin

Given:Present population = 5000Rate of growth = 3%Time = 10 years

Answered: A town with a population of 5,000…

Math

Algebra

A town with a population of 5,000 grows 3%per year. Find the population at the end of 10 years

College Algebra

10th Edition

ISBN:9781337282291

Author:Ron Larson

Publisher:Ron Larson

Chapter5: Exponential And Logarithmic Functions

Section5.5: Exponential And Logarithmic Models

Problem 30E: The table shows the mid-year populations (in millions) of five countries in 2015 and the projected...

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