A uniform 4 kg rod with length 46 m has a frictionless pivot at one end. The rod is released from rest at an angle of 23. beneath the horizontal. What is the angular acceleration of the rod immediately after it is released? The moment of inertia of a rod about the center of mass is 1/12 mL^2, where m is the mass of the rod and L is the length of the rod. The moment of inertia of a rod about either end is 1/3 mL^2. (Hint: Use rotational N2L. You should see that T=1/2 mgLcose since the weight acts through the center of mass of the rod and the rod is at an angle) 4 kg 23 m 23° 46 m Your answer

A uniform 4 kg rod with length 46 m has a frictionless pivot at one end. The rod is released from rest at an angle of 23. beneath the horizontal. What is the angular acceleration of the rod immediately after it is released? The moment of inertia of a rod about the center of mass is 1/12 mL^2, where m is the mass of the rod and L is the length of the rod. The moment of inertia of a rod about either end is 1/3 mL^2. (Hint: Use rotational N2L. You should see that T=1/2 mgLcose since the weight acts through the center of mass of the rod and the rod is at an angle) 4 kg 23 m 23° 46 m Your answer