A W18 3 119 is used as a compression member with one end fixed and the other end pinned. The length is 12 feet. What is the available compressive strength if A992 steel is used?
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A W18 3 119 is used as a compression member with one end fixed and the other end pinned. The length is 12 feet. What is the available compressive strength if A992 steel is used?
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- Determine the smallest value of yield stress Fy, for which a W-, M-, or S-shape from Part 1 of the Manual will become slender. To which shapes does this value apply? What conclusion can you draw from your answer?A W21 × 101 is used as a compression member with one end fixed and the other end free. The length is 9m. Fy = 345 MPa. 1. What are the slenderness limits for the W-section?2. What is the nominal compressive strength?For W12x65 A992 beam section with simple supports at span, L = 12 ft, Dead load = 300 lb/ft (Beam weight to be included), Live load = 800 lb/ft. Use ASD. What is the allowable shear strength of the beam section in kips? Express your answer in two decimal places.
- – A W530 × 150 is used as a compression member with one end fixed and the other end free. The length is 3 meters. What is the nominal compressive strength if Fy = 345 MPa?The following figure shows a cantilever beam with b = 305 mm containing three D-22 bars that are anchored in the column by standard 90 hooks. f. 42 MPa (normal-weight) and f=420 MPa. If the steel is stressed to f, at the face of the column, can these bars (a) be by hooks into the column? The clear cover to the side of the hook is 70 mm: The clear cover to the bar extension beyond the bend is 51 mm. The joint is enclosed by ties at 150 mm o.c.FIND USING ASD and LRFD A W 14 x 500 is used as a beam to support a concrete floor system. The floor is to carrya total load of 120 kPa. The beam is simply supported over a span of 7 meters. Assumethe beam is laterally supported over its length, the allowable bending stress is 0.66Fy,and the allowable shear stress on gross section is 0.4Fy. Use A36 steel with Fy = 250MPa. Determine the following:a. center-to-center spacing of the beams without exceeding the allowable bendingstress;b. center-to-center spacing of the beams without exceeding the allowable shearstress.
- 1. An unsymmetrical flexural member consists of a 70 × 600 top flange, a 70 x 400 bottom flange, and a 12 × 180 web. a, Determine the Section Modulus. b. Determine the distance from the bottom of the shape to the horizontal plastic neutral axis. c. If A572 Grade 50 steel is used, what is the plastic moment MPy for the horizontal plastic neutral axis?– A W460 × 177 is used as a compression member with one end fixed and the other end fixed against rotation but free to translate. The length is 3.70 meters. If A992 steel is used, what is the available compressive strength? Compute both the design strength for LRFD and the allowable strengthfor ASD.Given the truss shown, solve the following. Use A36 steel and assume there are two lines of three 19 mm bolts in each flange. Hole diameter is assumed to be three mm more than the bolt diameter. Neglect the weight of the section. a.What is the capacity of member CG? b. Design member CG using a W section. c. What is the tensile capacity of the section for CG based on gross area?
- Read the question carefully and give me right solution according to the question. A W12x79 of A573 Grade 60 (Fy=415 MPa) steel is used as a compression member. It is 8 m long, pinned at the top fixed at the bottom, and has additional support in the weak direction at mid-height. Properties of the section are as follows: A = 14,500 mm^2 Ix = 258.6 x 10^6 mm^4 Iy = 84.375 x 10^6 mm^4 Calculate the effective slenderness ratio with respect to strong axis buckling using theoretical value of k.A W14 x 74 of A992 steel has a length of 20 feet and pinned ends. Compute the design compressive strength for LRFD and the allowable compressive strength for ASD.Determine whether the compression members shown in the figure is adequate to support the given service loads. a. Use LRFD. b. Use ASD.