(a) What is the advantage of using MOSFET as compared to BJT at the first stage of multi-stage amplifier?

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Vsis (~
Q3 (a) What is the advantage of using MOSFET as compared to BJT at the first stage of
multi-stage amplifier?
Rais
600 02
www
Z₁
(b) Describe the function of the capacitor for the following condition:
(1)
(ii)
SEEE/SKEE 1073
(c)
The transistors parameters in Figure Q.3 are given as follow:
BJT
(iv)
↑
B-350, VBE 0.7 V, Ic=0.3 mA, VT 26 mV, and ro=00
E-MOSFETk 0.8 mA/V², VT- Vas(T) = 1 V
C₁
HE
a capacitor between stage 1 and stage 2 of a RC-coupled amplifier.
bypass capacitor which is commonly used in small signal amplifier.
(i) Draw the ac equivalent circuit at middle frequency for circuit in Figure Q.3
by using hybrid-x model.
(ii) Determine the values of Z., Ziz and Zo.
(iii) Calculate the gain, v/v, in decibel (dB).
Draw and label the waveforms vo when v=2 sin 50t [mV] for one complete
cycle.
+
Roi
50 ΚΩ
Vi Ra
6 kn
Ro
4.5 k
Q₁
Rs
3 kQ
C₂
не
+15 V
DS
↑
22
R₁
75 k
R₂
9 kn
Figure Q.3 Multistage amplifier circuit
Re
<5kQ C₁
Q₂
> RE
2kQ
Rez
1kQ
←
2₂
-C₁
R₂
20k2 %
Transcribed Image Text:Vsis (~ Q3 (a) What is the advantage of using MOSFET as compared to BJT at the first stage of multi-stage amplifier? Rais 600 02 www Z₁ (b) Describe the function of the capacitor for the following condition: (1) (ii) SEEE/SKEE 1073 (c) The transistors parameters in Figure Q.3 are given as follow: BJT (iv) ↑ B-350, VBE 0.7 V, Ic=0.3 mA, VT 26 mV, and ro=00 E-MOSFETk 0.8 mA/V², VT- Vas(T) = 1 V C₁ HE a capacitor between stage 1 and stage 2 of a RC-coupled amplifier. bypass capacitor which is commonly used in small signal amplifier. (i) Draw the ac equivalent circuit at middle frequency for circuit in Figure Q.3 by using hybrid-x model. (ii) Determine the values of Z., Ziz and Zo. (iii) Calculate the gain, v/v, in decibel (dB). Draw and label the waveforms vo when v=2 sin 50t [mV] for one complete cycle. + Roi 50 ΚΩ Vi Ra 6 kn Ro 4.5 k Q₁ Rs 3 kQ C₂ не +15 V DS ↑ 22 R₁ 75 k R₂ 9 kn Figure Q.3 Multistage amplifier circuit Re <5kQ C₁ Q₂ > RE 2kQ Rez 1kQ ← 2₂ -C₁ R₂ 20k2 %
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