(a) What is wrong with the following equation? x2 + x – 20 = x + 5 (x - 4)(x + 5) # x2 + x - 20 O The left-hand side is not defined for x = 0, but the right-hand side is. O The left-hand side is not defined for x = 4, but the right-hand side is. O None of these – the equation is correct. (b) In view of part (a), explain why the equation lim x2 + x – 20 х — 4 = lim (x + 5) is correct. x² + x – 20 and x + 5 are both continuous, the equation follows. Since O Since the equation holds for all x + 4, it follows that both sides of the equation approach the same limit as x → 4. O This equation follows from the fact that the equation in part (a) is correct. O None of these – the egquation is not correct. Need Help? Read It Talk to a Tutor
(a) What is wrong with the following equation? x2 + x – 20 = x + 5 (x - 4)(x + 5) # x2 + x - 20 O The left-hand side is not defined for x = 0, but the right-hand side is. O The left-hand side is not defined for x = 4, but the right-hand side is. O None of these – the equation is correct. (b) In view of part (a), explain why the equation lim x2 + x – 20 х — 4 = lim (x + 5) is correct. x² + x – 20 and x + 5 are both continuous, the equation follows. Since O Since the equation holds for all x + 4, it follows that both sides of the equation approach the same limit as x → 4. O This equation follows from the fact that the equation in part (a) is correct. O None of these – the egquation is not correct. Need Help? Read It Talk to a Tutor
College Algebra
7th Edition
ISBN:9781305115545
Author:James Stewart, Lothar Redlin, Saleem Watson
Publisher:James Stewart, Lothar Redlin, Saleem Watson
Chapter1: Equations And Graphs
Section1.4: Solving Quadratic Equations
Problem 3E: Far the quadratic equation ax2+bx+c=0 the discriminant is D = ______________. The discriminant tells...
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