a) Write a function to get the value of the Në node in a Linked List. [Note: The first (N=1) item in the list means the item at index 0.] It takes two parameters: the list or its head, and N. Return False if the list has fewer than N elements. The Linked List structure supports the following function. det getlead(self): return self.head # it points to a Node structure The Node structure supports the following functions. def getData(self): retun self.data # it returns the value stored in the Node def getNext(self): return self.next # it points to the next Node b) Write a function that counts the number of times a given integer occurs in a Linked List. Assume similar structures as defined in 1.
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- struct node{int num;node *next, *before;};start 18 27 36 45 54 63 The above-linked list is made of nodes of the type struct ex. Your task is now to Write a complete function code to a. Find the sum of all the values of the node in the linked list. b. Print the values in the linked list in reverse order. Use a temporary pointer temp for a and b. i dont need a full code just the list part8.14 LAB: Mileage tracker for a runner Given the MileageTrackerNode class, complete main() to insert nodes into a linked list (using the InsertAfter() function). The first user-input value is the number of nodes in the linked list. Use the PrintNodeData() function to print the entire linked list. DO NOT print the dummy head node. Ex. If the input is: 3 2.2 7/2/18 3.2 7/7/18 4.5 7/16/18 the output is: 2.2, 7/2/18 3.2, 7/7/18 4.5, 7/16/18 Main.cpp: #include "MileageTrackerNode.h"#include <string>#include <iostream>using namespace std; int main (int argc, char* argv[]) {// References for MileageTrackerNode objectsMileageTrackerNode* headNode;MileageTrackerNode* currNode;MileageTrackerNode* lastNode; double miles;string date;int i; // Front of nodes listheadNode = new MileageTrackerNode();lastNode = headNode; // TODO: Read in the number of nodes // TODO: For the read in number of nodes, read// in data and insert into the linked list // TODO: Call the PrintNodeData()…8.14 LAB: Mileage tracker for a runner Given the MileageTrackerNode class, complete main() to insert nodes into a linked list (using the InsertAfter() function). The first user-input value is the number of nodes in the linked list. Use the PrintNodeData() function to print the entire linked list. DO NOT print the dummy head node. Ex. If the input is: 3 2.2 7/2/18 3.2 7/7/18 4.5 7/16/18 the output is: 2.2, 7/2/18 3.2, 7/7/18 4.5, 7/16/18 Main.cpp: #include "MileageTrackerNode.h"#include <string>#include <iostream>using namespace std; int main (int argc, char* argv[]) {// References for MileageTrackerNode objectsMileageTrackerNode* headNode;MileageTrackerNode* currNode;MileageTrackerNode* lastNode; double miles;string date;int i; // Front of nodes listheadNode = new MileageTrackerNode();lastNode = headNode; // TODO: Read in the number of nodes // TODO: For the read in number of nodes, read// in data and insert into the linked list // TODO: Call the PrintNodeData()…
- 8.14 LAB: Mileage tracker for a runner Given the MileageTrackerNode class, complete main() to insert nodes into a linked list (using the InsertAfter() function). The first user-input value is the number of nodes in the linked list. Use the PrintNodeData() function to print the entire linked list. DO NOT print the dummy head node. Ex. If the input is: 3 2.2 7/2/18 3.2 7/7/18 4.5 7/16/18 the output is: 2.2, 7/2/18 3.2, 7/7/18 4.5, 7/16/18 Main.cpp #include "MileageTrackerNode.h"#include <string>#include <iostream>using namespace std; int main (int argc, char* argv[]) {// References for MileageTrackerNode objectsMileageTrackerNode* headNode;MileageTrackerNode* currNode;MileageTrackerNode* lastNode; double miles;string date;int i; // Front of nodes listheadNode = new MileageTrackerNode();lastNode = headNode; // TODO: Read in the number of nodes // TODO: For the read in number of nodes, read// in data and insert into the linked list // TODO: Call the PrintNodeData()…8.14 LAB: Mileage tracker for a runner Given the MileageTrackerNode class, complete main() to insert nodes into a linked list (using the InsertAfter() function). The first user-input value is the number of nodes in the linked list. Use the PrintNodeData() function to print the entire linked list. DO NOT print the dummy head node. Ex. If the input is: 3 2.2 7/2/18 3.2 7/7/18 4.5 7/16/18 the output is: 2.2, 7/2/18 3.2, 7/7/18 4.5, 7/16/18 Main.cpp #include "MileageTrackerNode.h"#include <string>#include <iostream>using namespace std; int main (int argc, char* argv[]) {// References for MileageTrackerNode objectsMileageTrackerNode* headNode;MileageTrackerNode* currNode;MileageTrackerNode* lastNode; double miles;string date;int i; // Front of nodes listheadNode = new MileageTrackerNode();lastNode = headNode; // TODO: Read in the number of nodes // TODO: For the read in number of nodes, read// in data and insert into the linked list // TODO: Call the PrintNodeData()…Computer Science In c++ (There should be three different files, "main.cpp", "sourcefile.cpp" and "header.cpp" your solution must have those three different files): Write a function that checks if the nodes in a linked list is sorted in ascending order. The function should return true if the values are sorted, otherwise false. Take user input. Call the funciton in the main function to show it is working.
- def normal (L): '' '(list of int) -> list Precondition: len (L)> = 1 This function must return a new list R which has the same contents of L except where there is a sequence of consecutive zeros, the list R must have only one zero such that in the examples: >>> normal ([1,2,0,0,0,3,0]) [1, 2, 0, 3, 0] >>> normal ([1,2,0,0,0,3,0,0,0,0]) [1, 2, 0, 3, 0] >>> normal ([0,0,1,0,2,0,0,0,3,0,0,0,0,0]) [0, 1, 0, 2, 0, 3, 0] >>> normal ([1,2,2,0,3,3,3,0]) [1, 2, 2, 0, 3, 3, 3, 0] '' ' [1, 2, 0, 3, 0] >>> tanganyika([1,2,0,0,0,3,0,0,0,0]) [1, 2, 0, 3, 0] >>> tanganyika([0,0,1,0,2,0,0,0,3,0,0,0,0]) [0, 1, 0, 2, 0, 3, 0] >>> tanganyika([1,2,2,0,3,3,3,0]) [1, 2, 2, 0, 3, 3, 3, 0] ''' Please: Do not use dictionaries.- Do not use sets- Do not use 'break'.- You cannot import a library or other moduleJAVA CODE PLEASE Linked List Practice ll by CodeChum Admin Write a function printNodes that takes in the head of a linked list and prints all the values of that linked list using a while loop. Print the values separated by a [space]->[space] In the main function, write a program that asks the user to input five integers and assign these values to the nodes. Arrange the nodes in ascending order first before printing them using the printNodes function. Input 1. One line containing an integer 2. One line containing an integer 3. One line containing an integer 4. One line containing an integer 5. One line containing an integer Output Enter·number·1:·1 Enter·number·2:·2 Enter·number·3:·3 Enter·number·4:·4 Enter·number·5:·5 1·->·2·->·3·->·4·->·5Please fill in the blanks for C /* This program will print students’ information and remove students using linked list: */ #include<stdio.h> #include<stdlib.h> //Declare a struct student (node) with 5 members //each student node contains an ID, an age, graduation year, // 1 pointer points to the next student, and 1 pointer points to the previous student. struct student { int ID; int age; int classOf; __1__ __2__ next; __3__ __4__ prev; }; /* - This function takes the head pointer and iterates through the list to get all 3 integers needed from the user, and save it to our list - Update the pointer to point to the next node. */ __5__ scanLL(__6__ __7__ head) { while(__8__ __9__ __10__) //this condition makes sure the list is not at the end { printf("Lets fill in the information. Enter 3 integers for the student's ID, age, and graduation year: ");…
- Create two linked lists and then make a concatList(NODE **list1, NODE **list2) function that concatenates the two lists. The concatenated list must be a linked list. Fill in the "Write code here" sections appropriately.Topic: Singly Linked ListImplement the following functions in C++ program. Read the question carefully. (See attached photo for reference) int removeAt(int pos) Removes the number in the posth position of the list and returns the element removed. Performing removeAt(3) in the example list will remove the 3rd element of the linked list and the updated list will be: 10 -> 30 -> 50 When the value of pos is greater than the size or less than one, return -1. int removeAll(int num) Removes all instances of num in the linked list and returns the number of instances removed. In this list 10 -> 10 -> 20 -> 30 -> 10, performing removeAll(10) will remove all three 10's and the list will look like this: 20 -> 30. Then, it will return the number of instances removed, in this case, 3. int contains(int num) This will return the position of the first instance of the element num in the list. If num is not found, return 0. In the example, having the method contains(30) will…_!?8. Problem Title: "Add Two Numb You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order, and each of their nodes contains a single digit. Add the two numbers and return the sum as a linked list. You may assume the two numbers do not contain any leading zero, except the number 0 itself..