Q: х3 + 2x2 + х 1. iim х->-1 2x2 —— х — 3 х3 + 2x? + 7х 2. lim X→-2 2х — 3 х3 + x2 + 4x 3. lim X→ー3 2x2
A: 1) limx→-1x3+2x2+x2x2-x-3Apply L-Hospital Rulelimx→-13x2+4x+14x-1=3(-1)2+4(-1)+14(-1)-1=3-4+1-4-1=-1...
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A: We can find the derivative as below.
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A: Topic = Functions
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A: There is a jump discontinuity at x=2 and f(2)=3
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A: We can find the answer as below in simplified form.
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- By applying limh → 0f (x + h) −f (x) h, at a point (a, 1 / a) of the function f (x) = 1x, it is obtained as slope (m): choose one to. 1 / a3 b. 1 / a2 c. −1 / a3 d. −1 / 2a need a bit help with this1. For what value (s) of x is the function f(x) = 4/2x2 - 6x not continous? 2. If the demand of firm is QD (p) = 50 -3p and its supply function is Qs (p) = 14 + 6p. What is the equilibrium? 3. Find Lim x2 -4x + 3/5Which of the following statements about the function y = ƒ(x)graphed here are true, and which are false? limx →3+ƒ(x) does not exist.
- If lim as t approaches 4 of the function ((g(x)-6)/(t-1))=1. Find lim t approaches 4 of g(t).The percentage of movie advertising as a share of newspapers' total advertising revenue from 1995 to 2004 could be approximated by p(t) = −0.07t + 5.0 if t ≤ 3 0.3t + 12.0 if t > 3 where t is time in years since 1995. Compute lim p(t) t→3− Compute lim p(t) t→3+For f(x)=√7x+2, find f′(x) using the definition f′(x)=limh→0f(x+h)−f(x)/h. f′(x)= Using this, find the tangent line to the graph of y=√7x+2 at x=1. Enter all values as integers, or fractions in lowest terms. y=
- I need to simplify the function algebraically to determine the limit. I know the initial substitution of x =a yields the form 0/0. I also know the answer is 7/2, but I'm not sure how to get there. Equation: lim x->1 ((x2 + 5x - 6)/(x2 - 1))If 1/(x^2 + 1) ≤ f(x) ≤ 1 + x^2 for all x in the interval (−1, 1), what is lim x→0 f(x)?For all x ≥ 0, 4x − 9 ≤ f(x) ≤ x2 − 4x + 7. Find limx→4f(x). ⇒