a) y(t)=ce²t cos(5 t) + c₂e² sin c)y(t)=ce²t cos(√5 t) + c₂et sin (√5 t) Q8) The inverse Laplace transform of H(s) d) y(t) = ce cos(5 t) + c 1 is: F T (35+2)(5-2) 2t a) f(t)=e+ b) f(t) ==e+ 8 1-2t +²e²t d)f(t)= c) f(t) ==e+e om The solution of y" + y'= 0 by using power series method, is: -2t h) y(x) = a + a₂ (1
a) y(t)=ce²t cos(5 t) + c₂e² sin c)y(t)=ce²t cos(√5 t) + c₂et sin (√5 t) Q8) The inverse Laplace transform of H(s) d) y(t) = ce cos(5 t) + c 1 is: F T (35+2)(5-2) 2t a) f(t)=e+ b) f(t) ==e+ 8 1-2t +²e²t d)f(t)= c) f(t) ==e+e om The solution of y" + y'= 0 by using power series method, is: -2t h) y(x) = a + a₂ (1
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter7: Analytic Trigonometry
Section7.6: The Inverse Trigonometric Functions
Problem 92E
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